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Rectangular waveguide modes and critical parameters

Short answer

Rectangular waveguide is a hollow metal pipe supporting TE and TM modes above cut-off, acting as a high-pass filter. The dominant TE10 mode has cut-off frequency fc=c/(2a), guide wavelength λg=λ0/√(1−(fc/f)²), phase velocity vp > c, and group velocity vg < c. Parameters depend on mode indices m and n and waveguide dimensions a (broad) and b (narrow).

Describe rectangular waveguide based on modes of propagation and other critical parameters.

A rectangular waveguide is a hollow metal pipe of inner width a and height b (a > b, often a ≈ 2b). Being a single conductor, it cannot carry TEM waves; it carries TE and TM modes above their cut-off frequencies, acting as a high-pass filter.

   y
 b +-----------------+
   |   E (TE10)  ↑   |   propagation along z
   +-----------------+
   0                 a  -> x

Modes of propagation

  • TEmn (H modes): Ez = 0, Hz = H0 cos(mπx/a) cos(nπy/b). m, n = 0, 1, 2 … but not both zero. Lowest: TE10.
  • TMmn (E modes): Hz = 0, Ez = E0 sin(mπx/a) sin(nπy/b). m, n ≥ 1. Lowest: TM11.
  • m and n are the numbers of half-wave field variations along the broad (a) and narrow (b) walls.
  • Dominant mode: TE10 (lowest fc). Degenerate modes: TEmn and TMmn with the same m, n share the same fc.

Critical parameters (air-filled)

ParameterExpression
Cut-off frequencyfc = (c/2)√((m/a)² + (n/b)²)
Cut-off wavelengthλc = 2/√((m/a)² + (n/b)²); TE10: 2a
Phase constantβ = (2π/λ0)√(1 − (fc/f)²)
Guide wavelengthλg = λ0/√(1 − (fc/f)²)
Phase velocityvp = c/√(1 − (fc/f)²) > c
Group velocityvg = c√(1 − (fc/f)²) < c
TE wave impedanceZ_TE = η/√(1 − (fc/f)²)
TM wave impedanceZ_TM = η√(1 − (fc/f)²)

Also 1/λ0² = 1/λg² + 1/λc² and vp·vg = c².

Example (WR-90, a = 2.286 cm, b = 1.016 cm, f = 10 GHz, TE10): fc = 6.562 GHz, λg = 3.976 cm, vp = 3.976 × 10⁸ m/s, vg = 2.264 × 10⁸ m/s, Z_TE ≈ 500 Ω. TE20 cuts off at 13.12 GHz, so only TE10 propagates.

✓ Answer checked by Claude Opus 5.5 (high effort)

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