- Practice · 5 marks
Rayleigh-Ritz and finite difference methods
Short answer
Rayleigh-Ritz approximates mode shape as a series of admissible functions and makes Rayleigh’s quotient stationary, giving an eigenvalue problem for upper-bound frequencies. Finite difference replaces spatial derivatives with difference formulas at grid points, forming a discrete eigenvalue problem whose accuracy increases with finer discretization.
Write short notes on the Rayleigh-Ritz method and the finite difference method for finding natural frequencies.
Rayleigh-Ritz method
It improves Rayleigh's quotient by using a trial function with several adjustable constants.
- Assume the mode shape as a series of admissible functions (satisfying the geometric boundary conditions):
- Write the Rayleigh quotient , where is the maximum strain energy and is the kinetic energy expression with taken out.
- Make stationary with respect to every constant:
This gives , an eigenvalue problem of order . 4. The roots approximate the lowest natural frequencies, always as upper bounds. More terms give better accuracy, and the higher modes are less accurate.
Finite difference method
It replaces the derivatives in the differential equation by differences between displacements at equally spaced stations.
For a beam divided into stations a distance apart:
Procedure:
- Divide the system into segments and write the governing equation, e.g. , at every interior station.
- Apply the boundary conditions (e.g. and at a simple support) using extra fictitious stations if necessary.
- The result is , solved as an eigenvalue problem.
Accuracy improves as decreases, but the order of the matrix grows. For a uniform beam, 4 to 6 segments already give the first frequency within a few percent.
| Point | Rayleigh-Ritz | Finite difference |
|---|---|---|
| Based on | Energy (variational) | Differential equation |
| Unknowns | Constants of trial functions | Displacements at stations |
| Result bound | Upper bound | No fixed bound |
✓ Answer checked by Claude Opus 5.5 (high effort)
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