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Rayleigh-Ritz method and its steps

Short answer

The Rayleigh–Ritz method makes the total potential energy Π = U − W stationary. Steps: (1) write Π; (2) choose trial function ũ = Σ aᵢφᵢ satisfying essential BCs; (3) substitute to get Π(aᵢ); (4) set ∂Π/∂aᵢ=0; (5) solve for aᵢ. Limitations: needs a functional, difficult for complex domains; FEM applies the Ritz concept element by element.

Write short notes on the Rayleigh-Ritz method. Explain its steps and state its limitations.

The Rayleigh-Ritz method is a variational method. Instead of solving the differential equation, it finds an approximate solution that makes a functional (the total potential energy Π\Pi) stationary. For a stable elastic system, the stationary point is a minimum.

Steps

  1. Write the functional. For elastic bodies, Π=U−W\Pi = U - W (strain energy minus work of external loads). For a bar, Π=12∫0LAE(dudx)2dx−∫0Lfu dx−Pu(L)\Pi = \dfrac{1}{2}\displaystyle\int_0^L AE\left(\dfrac{du}{dx}\right)^2dx - \int_0^L f u\,dx - Pu(L).
  2. Choose a trial function with unknown coefficients:
u(x)≈∑i=1nai ϕi(x)u(x) \approx \sum_{i=1}^{n} a_i\,\phi_i(x)

The functions ϕi\phi_i must be continuous, independent and must satisfy the essential (geometric) boundary conditions. 3. Substitute into Π\Pi so that it becomes a function of a1,a2,…,ana_1, a_2, \dots, a_n. 4. Make Π\Pi stationary: ∂Π∂ai=0\dfrac{\partial \Pi}{\partial a_i} = 0 for i=1,…,ni = 1, \dots, n. This gives nn algebraic equations [K]{a}={F}[K]\{a\} = \{F\}. 5. Solve for aia_i and compute displacement, strain and stress.

Remarks

  • Natural boundary conditions need not be satisfied by the trial function; they come out of the minimisation.
  • More terms give a better answer. The computed stiffness is never less than the true stiffness (the displacement is underestimated), so the method gives a bound.
  • If the trial function includes the exact solution, the result is exact.

Limitations

  • Choosing one trial function for the whole domain is hard for complex shapes.
  • It needs a functional, which exists only for self-adjoint problems.
  • FEM removes this difficulty by applying the Ritz idea element by element with simple local trial functions.

✓ Answer checked by Claude Opus 5.5 (high effort)

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