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Design factors of rotary intersection

Short answer

Key factors are design speed, central island radius, entry and exit curve radii, weaving length and width, carriageway width, entry and non-weaving widths, central island shape, proportion of weaving traffic, superelevation, sight distance, and channelising islands.

Explain the design factors to be considered in rotary intersection design.

Design elements/factors for a rotary (IRC:65-1976, Recommended Practice for Traffic Rotaries)

  1. Design speed: 30 km/h for urban and 40 km/h for rural rotaries (IRC:65).
  2. Radius of the central island and entry/exit curves: the central island radius is about 1.33 times the entry curve radius (IRC:65); the entry curve radius is about 20 m (urban) to 25 m (rural); exit curves are about 1.5 to 2 times the entry curve radius, to speed up exits.
  3. Weaving length and width: the weaving length between the entry and exit of consecutive arms should be at least 4 times the weaving width (IRC:65), and is checked so that w/lw/l lies between 0.12 and 0.4 for the capacity formula.
  4. Width of the rotary carriageway: the width of the weaving section is the average of the entry width and the non-weaving width plus 3.5 m (w=(e1+e2)/2+3.5w = (e_1 + e_2)/2 + 3.5 m); minimum 7 m for a rotary on two-lane approaches.
  5. Entry and exit widths: the entry width e1e_1 and non-weaving width e2e_2 are provided to suit the approach carriageways, keeping e/we/w between 0.4 and 1.0.
  6. Shape of the central island: circular (preferred), elliptical, tangent or turbine shapes to suit the angles of the approach roads.
  7. Traffic volume and proportion of weaving traffic: the capacity formula depends on this proportion pp (0.4-1.0).
  8. Super-elevation and cross slope: the carriageway is given a reverse camber of about 1.5 to 2 percent (cross fall outward) for drainage; no superelevation inwards.
  9. Sight distance at entries and in the circulating carriageway.
  10. Channelising islands, pedestrian refuges, markings, signs and lighting.

Capacity check: the practical capacity of the weaving section (IRC:65, Wardrop/TRRL formula) is

Qp=280 w(1+ew)(1−p3)1+wl PCU/hQ_p = \frac{280\,w\left(1+\dfrac{e}{w}\right)\left(1-\dfrac{p}{3}\right)}{1+\dfrac{w}{l}}\ \text{PCU/h}

where e=(e1+e2)/2e = (e_1+e_2)/2, ww = weaving width (m), ll = weaving length (m), and pp = proportion of weaving traffic to total traffic in the weaving section. The formula is valid when 0.4≤e/w≤1.00.4 \le e/w \le 1.0, 0.12≤w/l≤0.40.12 \le w/l \le 0.4, 0.4≤p≤1.00.4 \le p \le 1.0 and ww lies between 6 and 18 m.

✓ Answer checked by Claude Opus 5.5 (high effort)

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