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Characteristic form FD solution (velocity, pressure)
Short answer
Converted to ODEs along dx/dt = ±a: dV/dt ± (1/ρa) dp/dt + g sinθ + (f/2D)V|V| = 0. Finite-difference integration over Δx = aΔt gives C⁺: p_P = p_A − ρa(V_P−V_A) − ρg(z_P−z_A) − (ρfΔx/2D)V_A|V_A|, and C⁻: p_P = p_B + ρa(V_P−V_B) + ρg(z_B−z_P) + (ρfΔx/2D)V_B|V_B|; solving yields V_P and p_P.
Develop a characteristic form of a finite-difference solution of the unsteady flow equations to get the solution in terms of velocity and pressure.
Governing equations (velocity , pressure )
For a pipe of diameter inclined at angle to the horizontal (water density , wave speed , friction factor ), neglecting the small convective terms:
Momentum:
Continuity:
Characteristic equations
Form :
For both brackets to be total derivatives, , so and :
Finite difference form
Use the rectangular grid with A, C, B at time and P at , with . Multiply by , integrate along each characteristic (friction at the known point), and put (rise of the pipe over ):
t+dt : P
/ \
C+ / \ C-
t : A----C----B
Solution
Equating the two expressions for :
and is then obtained from either equation. At each time step, the interior points are found this way; boundary points use one characteristic plus the boundary condition (e.g. reservoir pressure, or at a closed valve).
✓ Answer checked by Claude Opus 5.5 (high effort)
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