- Practice · 5 marks
Truss, beam and frame element differences
Short answer
Truss: axial force only, 2 DOFs/node, 4×4 matrix. Beam: bending/shear, 2 DOFs/node (v,θ), 4×4 matrix. Frame: combined axial and bending, 3 DOFs/node (u,v,θ), 6×6 matrix. A transformation matrix rotates local stiffness to a global coordinate system because members are oriented at different angles; it uses direction cosines for truss and extends to 6×6 for frame elements.
Differentiate between truss, beam and frame elements in the direct stiffness method. Write the degrees of freedom per node and the size of the element stiffness matrix for each in two dimensions, and explain the need for a transformation matrix.
Comparison (2D)
| Point | Truss element | Beam element | Frame element |
|---|---|---|---|
| Load carried | Axial force only | Transverse load, bending, shear | Axial + bending + shear |
| DOF per node | 2 (, ) in global axes | 2 (, ) | 3 (, , ) |
| Element matrix size | |||
| Joint type | Pin (no moment) | Rigid, collinear members | Rigid joint |
| Stiffness terms | , , ... | Both and terms | |
| Orientation | Any angle | Along the x-axis | Any angle |
The local frame element matrix is the bar matrix for combined with the beam matrix for :
Need for transformation
Members of a truss or frame lie at different angles, but the global equations must be written in one common (global) - system. The element matrix derived along the member axis (local) is converted by
For a truss element, with and :
For a frame element, is a matrix with the rotation unchanged. Beam elements all lie along one axis, so no transformation is needed.
✓ Answer checked by Claude Opus 5.5 (high effort)
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