- 2070 Asar · 4 marks
Delta-star and star-delta conversion
Short answer
Delta-to-star: R_A = R_AB·R_CA/(R_AB + R_BC + R_CA); similarly for R_B and R_C. Star-to-delta: R_AB = (R_A R_B + R_B R_C + R_C R_A)/R_C; similarly for R_BC and R_CA. These equivalences allow bridge circuit reduction.
Explain with neat diagram and write the equations for Delta- Star Conversion and for Star-Delta Conversion.
A delta (Δ) network of three resistors can be replaced by an equivalent star (Y) network, and the reverse, so that the resistance between each pair of terminals stays the same. This lets bridge circuits be reduced by series-parallel rules.
Delta Star
A A
/ \ |
Rab / \ Rca Ra
/ \ |
B-------C O
Rbc / \
Rb Rc
/ \
B C
Delta to star
Let the delta resistances be R_AB, R_BC, R_CA. Each star resistor equals the product of the two delta resistors touching that terminal divided by the sum of all three:
- R_A = R_AB × R_CA/(R_AB + R_BC + R_CA)
- R_B = R_AB × R_BC/(R_AB + R_BC + R_CA)
- R_C = R_BC × R_CA/(R_AB + R_BC + R_CA)
For equal delta resistors R_Δ, R_Y = R_Δ/3.
Star to delta
Let the star resistances be R_A, R_B, R_C. Let S = R_A R_B + R_B R_C + R_C R_A.
- R_AB = S/R_C
- R_BC = S/R_A
- R_CA = S/R_B
(Each delta resistor is the sum of products divided by the star resistor opposite to it.) For equal star resistors R_Y, R_Δ = 3 R_Y.
Derivation idea
Equate the resistance between each pair of terminals with the third terminal open. For example, between A and B: R_A + R_B = R_AB ∥ (R_BC + R_CA). Solving the three equations gives the formulae above.
Example
A delta of 30 Ω, 30 Ω, 30 Ω gives a star of 10 Ω, 10 Ω, 10 Ω.
✓ Answer checked by Claude Opus 5.5 (high effort)
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