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Sabine's formula and good acoustics
Short answer
A good hall has optimum reverberation time, uniform loudness, no echoes, and low noise; studying reverberation time balances absorption. Sabine's formula T = 0.161 V/Σ aS (seconds) follows from dE/dt =−EcA/4V.
Write the features of an acoustically good hall/auditorium (and why reverberation time must be studied before building one). Derive Sabine's formula, the relation for reverberation time in terms of absorption coefficient, volume and surface area of the hall.
Features of an acoustically good hall
- Optimum reverberation time: neither too long (speech becomes blurred as echoes overlap) nor too short (sound dull and weak). About 1 to 1.5 s for speech halls, 1.5 to 2.5 s for music halls.
- Adequate loudness at every seat; sound reflected from walls and ceiling adds to the direct sound.
- Uniform distribution of sound, with no dead spots or focal points; avoid concave surfaces or use diffusers.
- No echoes or sound shadows; delayed reflections (more than about 0.1 s) are avoided.
- Good diffusion by irregular wall surfaces, and no resonance of walls or objects.
- Low background noise: sound insulation from outside, quiet ventilation.
Why reverberation time must be studied first: it decides the balance of absorbing and reflecting surfaces needed. If the hall is built without calculating it, the speech will be unclear (too long a time) or lifeless (too short), and correcting it afterwards is costly.
Sabine's formula
Reverberation time T is the time taken for the sound intensity to fall to 10⁻⁶ of its initial value (a fall of 60 dB) after the source stops.
Let V = volume of the hall, S1, S2, … surfaces with absorption coefficients a1, a2, …, and total absorption A = Σ aS. Let E be the sound energy density and c the speed of sound.
- Energy falling on unit area of a wall per second = Ec/4.
- Energy absorbed per second by all surfaces = (Ec/4) Σ aS = EcA/4.
- Rate of change of total energy in the hall: V dE/dt = −EcA/4.
- Integrating:
dE/E = −(cA/4V) dt → E = E0 e^(−cAt/4V)
- Reverberation time: E/E0 = 10⁻⁶ at t = T:
10⁻⁶ = e^(−cAT/4V)
T = (4V ln 10⁶) / (cA) = 4 × 13.82 V / (c A)
- With c = 343 m/s (air at about 20°C), 4 × 13.82/343 = 0.161:
T = 0.161 V / Σ aS = 0.161 V / (ā S)
where S is the total surface area and ā = ΣaS/S is the average absorption coefficient. This is Sabine's formula (V in m³, S in m², T in seconds). Larger V increases T; more absorbing surface reduces T.
✓ Answer checked by Claude Opus 5.5 (high effort)
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