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Controller for damping ratio of 1

Short answer

To achieve damping ratio of 1 (critical damping), use a PD controller or derivative output feedback. The derivative term increases effective damping without lowering natural frequency, yielding fastest non-overshooting response. Rate feedback gain Kt = 2(1-ζ)/ω_n.

If desired damping ratio is '1', which controller do you suggest? Explain.

To obtain a damping ratio of 1 (critical damping: fastest response with no overshoot), a controller that adds damping is needed: a PD (proportional–derivative) controller, or equivalently derivative (tachometer) output feedback. Gain adjustment alone cannot usually do it without making the response very slow.

Why PD

For a typical underdamped plant G(s)=ωn2s(s+2ζωn)G(s)=\dfrac{\omega_n^2}{s(s+2\zeta\omega_n)}, PD control Gc(s)=1+TdsG_c(s)=1+T_ds gives

C(s)R(s)=ωn2(1+Tds)s2+(2ζωn+Tdωn2)s+ωn2\frac{C(s)}{R(s)}=\frac{\omega_n^2(1+T_ds)}{s^2+(2\zeta\omega_n+T_d\omega_n^2)s+\omega_n^2} ζ′=ζ+Tdωn2\zeta'=\zeta+\frac{T_d\omega_n}{2}

The derivative term raises ζ while ωn\omega_n stays the same. For ζ′=1\zeta'=1:

Td=2(1−ζ)ωnT_d=\frac{2(1-\zeta)}{\omega_n}

With derivative output feedback (KtsK_ts in the minor loop), ζ′=ζ+Ktωn2\zeta'=\zeta+\frac{K_t\omega_n}{2}, so Kt=2(1−ζ)ωnK_t=\frac{2(1-\zeta)}{\omega_n}; this has no added zero, so the response is truly non-overshooting.

Why not others

ControllerEffect on ζ
P (lower gain)ζ rises but ωn\omega_n and speed fall; steady-state error rises
PIadds lag: ζ falls
PD / rate feedbackζ rises, speed kept

Example: G(s)=16s(s+2)G(s)=\dfrac{16}{s(s+2)}: ωn=4\omega_n=4, ζ=0.25\zeta=0.25. Rate feedback with Kt=2(1−0.25)4=0.375K_t=\dfrac{2(1-0.25)}{4}=0.375 gives s2+(2+6)s+16=(s+4)2s^2+(2+6)s+16=(s+4)^2, i.e. ζ=1\zeta=1, a critically damped response with ts≈5.8ωn=1.46t_s\approx\frac{5.8}{\omega_n}=1.46 s and no overshoot.

✓ Answer checked by Claude Opus 5.5 (high effort)

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