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R-H range of K for K(s+13)/[s(s+3)(s+7)]

Short answer

Characteristic equation: s³+10s²+(21+K)s+13K=0. Routh array requires K>0 from s⁰ row and (210−3K)/10>0 from s¹ row, giving K<70. The system is stable for 0 < K < 70.

Apply RH criteria to determine the range of 'K' for which a unity feedback system with G(s) = K(s+13)/[s(s+3)(s+7)] will be stable.

For unity feedback, the closed-loop characteristic equation is 1+G(s)=01+G(s)=0. The system is stable when the first column of the Routh array has no sign change.

Characteristic equation

1+K(s+13)s(s+3)(s+7)=0s(s2+10s+21)+Ks+13K=0s3+10s2+(21+K)s+13K=0\begin{aligned} 1 + \frac{K(s+13)}{s(s+3)(s+7)} &= 0 \\ s(s^2+10s+21) + Ks + 13K &= 0 \\ s^3 + 10s^2 + (21+K)s + 13K &= 0 \end{aligned}

Routh array

RowCol 1Col 2
s3s^3121+K21+K
s2s^21013K13K
s1s^110(21+K)−1(13K)10=210−3K10\frac{10(21+K)-1(13K)}{10}=\frac{210-3K}{10}0
s0s^013K13K

Conditions for stability

  1. From the s1s^1 row: 210−3K10>0⇒K<70\frac{210-3K}{10} > 0 \Rightarrow K < 70
  2. From the s0s^0 row: 13K>0⇒K>013K > 0 \Rightarrow K > 0
0<K<700 < K < 70

Marginal stability

At K=70K = 70 the s1s^1 row vanishes. Auxiliary equation:

10s2+13(70)=0⇒s2=−91⇒s=±j9.5410s^2 + 13(70) = 0 \Rightarrow s^2 = -91 \Rightarrow s = \pm j9.54

So at K=70K=70 the system oscillates at 9.54 rad/s, and for K>70K>70 two poles move into the RHP.

Answer: the system is stable for 0<K<700 < K < 70.

✓ Answer checked by Claude Opus 5.5 (high effort)

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