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R-H range of K for K/[(s+2)(s+4)(s²+6s+25)]

Short answer

The characteristic equation is s⁴+12s³+69s²+198s+(200+K)=0. Routh array gives stability for 0 < K < 666.25. Sustained oscillation occurs at K = 666.25 with frequency ω = 4.06 rad/s.

The open loop TF of a unity feedback control system is given as G(s) = K/[(s+2)(s+4)(s²+6s+25)]. Determine the range of gain K for the system to be stable. Also determine the value of K which will cause the sustained oscillation and corresponding oscillation frequency.

Write the closed-loop characteristic equation 1+G(s)=01+G(s)=0 and apply the Routh criterion. Sustained oscillation occurs when the s1s^1 row becomes zero, and the auxiliary equation from the s2s^2 row gives the frequency.

Characteristic equation

(s+2)(s+4)(s2+6s+25)+K=0(s2+6s+8)(s2+6s+25)+K=0s4+12s3+69s2+198s+(200+K)=0\begin{aligned} (s+2)(s+4)(s^2+6s+25) + K &= 0 \\ (s^2+6s+8)(s^2+6s+25) + K &= 0 \\ s^4 + 12s^3 + 69s^2 + 198s + (200+K) &= 0 \end{aligned}

Routh array

RowCol 1Col 2Col 3
s4s^4169200+K200+K
s3s^3121980
s2s^212(69)−19812=52.5\frac{12(69)-198}{12}=52.5200+K200+K
s1s^152.5(198)−12(200+K)52.5=7995−12K52.5\frac{52.5(198)-12(200+K)}{52.5}=\frac{7995-12K}{52.5}0
s0s^0200+K200+K

Range of K

  • s1s^1 row: 7995−12K>0⇒K<666.257995 - 12K > 0 \Rightarrow K < 666.25
  • s0s^0 row: 200+K>0⇒K>−200200 + K > 0 \Rightarrow K > -200
−200<K<666.25(for positive gain: 0<K<666.25)-200 < K < 666.25 \qquad (\text{for positive gain: } 0 < K < 666.25)

Value of K for sustained oscillation

Kmar=799512=666.25K_{mar} = \frac{7995}{12} = 666.25

Frequency of oscillation

Auxiliary equation from the s2s^2 row:

52.5s2+(200+666.25)=0s2=−866.2552.5=−16.5ω=16.5=4.062 rad/s\begin{aligned} 52.5s^2 + (200 + 666.25) &= 0 \\ s^2 &= -\frac{866.25}{52.5} = -16.5 \\ \omega &= \sqrt{16.5} = 4.062\ \text{rad/s} \end{aligned}

Check: with K=666.25K = 666.25 the roots are ±j4.062\pm j4.062 and −6±j4.062-6 \pm j4.062.

Answer: stable for 0<K<666.250 < K < 666.25; sustained oscillation at K=666.25K = 666.25 with ω=4.06\omega = 4.06 rad/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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