How to convert XS-3 to BCD?

Subtract 3 from each 4-bit group

Convert (1001 1010)excess-3 to BCD

Short answer

Subtract 0011 from each excess-3 nibble: 1001₂-0011₂=6, 1010₂-0011₂=7. Decimal 67 is represented in BCD as 0110 0111.

Convert (1001 1010)excess-3 = (?)BCD.

Subtract 3 (0011) from each group to get the decimal digit, then write it in BCD.

XS-3 group	− 3	Digit	BCD
1001 (9)	6	6	0110
1010 (10)	7	7	0111

Answer: $(1001\ 1010)_{XS-3} = (67)_{10} = (0110\ 0111)_{BCD}$

✓ Answer checked by Claude Opus 5.5 (high effort)