How is an excess-3 group turned into BCD?

Subtract 0011 (3) from each 4-bit group

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Convert (1010 0111)excess-3 to BCD

Short answer

Subtract 0011 from each 4-bit group: 1010-0011=0111 (7), 0111-0011=0100 (4). Result: (0111 0100)BCD.

Convert (1010 0111)excess-3 = (?)BCD.

Rule: an excess-3 (XS-3) code word is the BCD code of each decimal digit plus 3 (0011). So subtract 0011 from each 4-bit group to get the BCD digit.

XS-3 group	Value	Subtract 3	BCD
1010	10	10 − 3 = 7	0111
0111	7	7 − 3 = 4	0100

So the decimal number is 74.

Answer: $(1010\ 0111)_{XS\text{-}3} = (0111\ 0100)_{BCD}$ (= $74_{10}$ ).

✓ Answer checked by Claude Opus 5.5 (high effort)

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