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Convert (1100 0011)Excess-3 to BCD

Short answer

Subtract 0011 from each group: 1100−0011=1001 (9), 0011−0011=0000 (0). The BCD code is (1001 0000).

Convert (1100 0011)Excess-3 = (?)BCD.

Subtract 3 (0011) from each 4-bit group to get the decimal digit, then write it in BCD.

XS-3 group− 3DigitBCD
1100 (12)991001
0011 (3)000000

Answer: (1100 0011)XS−3=(90)10=(1001 0000)BCD(1100\ 0011)_{XS-3} = (90)_{10} = (1001\ 0000)_{BCD}

✓ Answer checked by Claude Opus 5.5 (high effort)

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