- 2078 Bhadra · 4+3 marks
K-map Σm(0,1,2,8,10,14,15)+d, POS with NOR
Short answer
Simplified POS: F = (A+B')(B'+C)(A'+B+D'). Standard POS: ΠM(4,5,6,7,9,11,12,13). Realized with NOR gates using NOR-NOR form and inverters.
Simplify Σm(0,1,2,8,10,14,15) d = (3,7,11,13) using k-map, write its standard product of sum expression and realize it using NOR gates only.
Given . The 0-cells are 4, 5, 6, 9, 12.
K-map (grouping the 0s for POS)
CD
AB 00 01 11 10
+---+---+---+---+
00 | 1 | 1 | X | 1 |
+---+---+---+---+
01 | 0 | 0 | X | 0 |
+---+---+---+---+
11 | 0 | X | 1 | 1 |
+---+---+---+---+
10 | 1 | 0 | X | 1 |
+---+---+---+---+
- Quad of 0s M(4,5,6,7) →
- Quad of 0s M(4,5,12,13) →
- Pair of 0s M(9,11) →
Check: 4, 5, 6 by ; 12 by ; 9 by . (, cells 9 and 13, is an equally good third term.)
Standard product of sums
The given 0s are with don't-cares . The simplified POS also makes don't-cares 7, 11, 13 equal to 0, so its standard (canonical) POS is:
Realization using NOR gates only
A POS expression maps directly to a two-level NOR-NOR circuit:
A ──[NOR]── A' (inputs tied)
B ──[NOR]── B' (inputs tied)
D ──[NOR]── D' (inputs tied)
A, B' ──[NOR]── P1 ─┐
B', C ──[NOR]── P2 ─┤──[NOR]── F
A', B, D' ──[NOR]── P3 ─┘
Gates: 3 NOR inverters (), two 2-input NORs, one 3-input NOR and one 3-input output NOR: 7 NOR gates.
✓ Answer checked by Claude Opus 5.5 (high effort)
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