- Asked 2/22
- 2081 Baisakh · 2+4 marks
Minterms/maxterms; K-map Σ(1,3,5,8,10,11,12)+d
Short answer
A minterm is an AND term with all variables, true for one input; a maxterm is an OR term with all variables, false for one input. Simplified: F = B'C + A'C'D + AC'D'. The circuit uses AND-OR gates with inverters.
Define min-terms and max-terms. Simplify the function using K-map, F = Σ(1,3,5,8,10,11,12) and D = Σ(2,9,15) and also realize the simplified logic circuit.
Min-terms and max-terms
A minterm is a product (AND) term that contains every variable of the function exactly once, in true or complemented form. It equals 1 for exactly one input combination. A variable is written true if its value is 1 and complemented if it is 0; e.g. for ABC = 101 the minterm is . A function in canonical SOP is a sum of minterms: .
A maxterm is a sum (OR) term that contains every variable exactly once, in true or complemented form. It equals 0 for exactly one input combination. A variable is written true if its value is 0 and complemented if it is 1; e.g. for ABC = 101 the maxterm is . A function in canonical POS is a product of maxterms: .
, and a function's minterm list and maxterm list are complementary (together they hold all numbers).
K-map simplification
CD
AB 00 01 11 10
+---+---+---+---+
00 | 0 | 1 | 1 | X |
+---+---+---+---+
01 | 0 | 1 | 0 | 0 |
+---+---+---+---+
11 | 1 | 0 | X | 0 |
+---+---+---+---+
10 | 1 | X | 1 | 1 |
+---+---+---+---+
- Pair m(1,5) →
- Pair m(8,12) →
- Quad m(2,3,10,11) →
Check: 3, 10, 11 by (with don't-care 2); 1, 5 by ; 8, 12 by . Don't-cares 9 and 15 are not needed.
Logic circuit (AND-OR)
B' ─┐
C ─┴─[AND]── B'C ────┐
A' ─┐ │
C' ─┼─[AND]── A'C'D ──┼─[OR]── F
D ─┘ │
A ─┐ │
C' ─┼─[AND]── AC'D' ──┘
D' ─┘
Complements come from NOT gates. The circuit needs one 2-input AND, two 3-input ANDs and one 3-input OR (plus inverters).
✓ Answer checked by Claude Opus 5.5 (high effort)
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