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Diffusion of carriers and conductivity

Short answer

Diffusion is carrier flow from high to low concentration due to thermal motion, producing current density J_diff = eD dn/dx (electrons) or −eD dp/dx (holes). It adds a drift-independent component, crucial in concentration gradients like pn junction forward current, but does not alter uniform bulk conductivity.

What do you understand by diffusion of charge carriers in semiconductor? How does diffusion contribute to conductivity of a semiconductor?

Diffusion of charge carriers is the movement of electrons or holes from a region of high concentration to low concentration due to their random thermal motion, even when no electric field is present. It occurs whenever the carrier concentration is non-uniform, e.g. near a pn junction or when light injects extra carriers at one end of a bar.

Why it happens

Carriers move randomly with thermal velocity. Across any plane, more carriers cross from the crowded side than from the sparse side, so there is a net flow down the gradient. By Fick's law the flux is

F=−DdndxF = -D\frac{dn}{dx}

where DD (cm² s⁻¹) is the diffusion coefficient.

Diffusion current

Je,diff=eDedndx,Jh,diff=−eDhdpdxJ_{e,diff} = eD_e\frac{dn}{dx},\qquad J_{h,diff} = -eD_h\frac{dp}{dx}
 n high  o o o o o o  -->  o   o    n low
         electrons diffuse -->
         electron current  <--

Contribution to conduction

  • Diffusion adds a second current component to the drift current, so the total is
Je=enμeE+eDedndxJ_e = en\mu_e\mathcal{E} + eD_e\frac{dn}{dx}
  • It lets current flow where there is little or no field, e.g. minority carriers crossing the base of a transistor or the neutral regions of a forward-biased diode. The forward current of a diode is essentially a diffusion current.
  • DD and μ\mu are linked by the Einstein relation D/μ=kT/eD/\mu = kT/e, so carriers with high mobility also diffuse quickly.
  • In equilibrium (e.g. a pn junction with no bias) diffusion is balanced by an equal and opposite drift current, so the net current is zero.

Thus diffusion does not change the bulk conductivity σ=e(nμe+pμh)\sigma = e(n\mu_e + p\mu_h) of a uniform sample, but in devices with concentration gradients it is often the main way current is carried.

✓ Answer checked by Claude Opus 5.5 (high effort)

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