Skip to main content

Types of stresses in thin walled cylinders

Short answer

Circumferential (hoop) stress = pd/(2t) acts tangentially, longitudinal = pd/(4t) axially, both tensile. Radial stress negligible. Maximum in-plane shear = pd/(8t). Hoop stress is twice the longitudinal, governing thickness design.

Explain the different types of stresses in thin walled cylinders.

A cylinder is called thin walled when the wall thickness is small compared with the diameter (t<d/20t < d/20). Under internal fluid pressure pp the wall is stressed in two principal directions; the radial stress is so small that it is neglected.

        hoop (circumferential)
          ^  ^  ^
   sl <--[=======]--> sl
        longitudinal

1. Circumferential (hoop) stress, σc\sigma_c

  • Acts tangentially around the circumference, tending to split the cylinder along a longitudinal section.
  • Considering half the cylinder: bursting force p d Lp\,d\,L = resisting force 2σc t L2\sigma_c\,t\,L.
σc=pd2t\sigma_c = \frac{pd}{2t}

2. Longitudinal (axial) stress, σl\sigma_l

  • Acts along the axis of the cylinder, tending to separate it along a circular (transverse) section.
  • Force on the ends p×π4d2p\times\frac{\pi}{4}d^2 = resisting force σl πd t\sigma_l\,\pi d\,t.
σl=pd4t\sigma_l = \frac{pd}{4t}

3. Radial stress

Varies from −p-p at the inner surface to zero at the outer surface; it is very small compared with the other two and is ignored in thin cylinders.

4. Maximum shear stress

With σc\sigma_c and σl\sigma_l as principal stresses, the maximum in-plane shear stress is

τmax=σc−σl2=pd8t\tau_{max} = \frac{\sigma_c-\sigma_l}{2} = \frac{pd}{8t}

Notes

  • σc=2σl\sigma_c = 2\sigma_l, so the hoop stress decides the thickness; a boiler shell fails along a longitudinal seam first.
  • Both stresses are tensile, and both are uniform over the thickness.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Strength of Materials chapter 5 questions →