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Water pipe thickness from pressure head

Short answer

Water pressure p = γh = 1 N/mm². Using hoop stress σ = pd/(2t), required thickness t = (1×500)/(2×20) = 12.5 mm (practically 13 mm).

A water pipe 500 mm internal diameter contains water at a pressure head 100 m. If the unit weight of water is 10 KN/m310\ \text{KN/m}^3 and allowable stress of pipe material is 20 N/mm220\ \text{N/mm}^2. Calculate the thickness of the pipe.

Data: internal diameter d=500d = 500 mm, pressure head h=100h = 100 m of water, γw=10 kN/m3\gamma_w = 10\ \text{kN/m}^3, allowable stress σ=20 N/mm2\sigma = 20\ \text{N/mm}^2.

Pressure in the pipe

p=γwh=10 kN/m3×100 m=1000 kN/m2=1 N/mm2p = \gamma_w h = 10\ \text{kN/m}^3\times100\ \text{m} = 1000\ \text{kN/m}^2 = 1\ \text{N/mm}^2

Thickness

The hoop stress is the larger stress, so it governs the design:

σc=pd2t⇒t=pd2σc=1×5002×20=12.50 mm\sigma_c = \frac{pd}{2t} \Rightarrow t = \frac{pd}{2\sigma_c} = \frac{1\times500}{2\times20} = 12.50\ \text{mm}

Check of the longitudinal stress: σl=pd4t=10.0 N/mm2<20\sigma_l = \dfrac{pd}{4t} = 10.0\ \text{N/mm}^2 < 20, safe.

Answer: thickness t=12.5 mmt = 12.5\ \text{mm} (provide 13 mm or more in practice).

✓ Answer checked by Claude Opus 5.5 (high effort)

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