- 2058 Chaitra · 10 marks
Angle misclosure, closed link traverse AT1-ET2
Short answer
Angle misclosure 40'' (computed ET2 105°35'28''). Correction +8'' per angle, giving adjusted bearings: T1A 339°09'21'', AB 81°26'47'', BC 168°15'08'', CD 77°32'09'', DE 354°08'22'', ET2 105°36'08''.
Compute the angle misclosure and adjusted bearings in the following closed link traverse. Adjusted bearing AT1 = 329°09′21″ [?]. Adjusted bearing ET2 = 105°36′08″. Angles (angles to the right): A = 282°17′18″, B = 266°48′13″, C = 89°16′53″, D = 96°36′05″, E = 291°27′38″.
Reading of the data. The first bearing is printed as 329°09′21″ [?]. If 329°09′21″ is taken as the bearing of the line from T1 to A, the computed bearing of ET2 comes out as 95°35′28″, a misclosure of about 10°00′40″, which is impossible for angles measured to the second. The value consistent with the other data is 339°09′21″ for the line from T1 to A (its reverse bearing, from A to T1, is 159°09′21″). That value is used below. The angles are to the right, so the bearing of each forward line = bearing of the previous line + 180° + angle at the station.
Rule (angles to the right): (add or subtract to bring the result between and ).
Step 1: Bearings computed from the observed angles
| Line | Working | Computed FB |
|---|---|---|
| T1-A | given | 339°09′21″ |
| A-B | 339°09′21″ + 180° + 282°17′18″ − 720° | 81°26′39″ |
| B-C | 81°26′39″ + 180° + 266°48′13″ − 360° | 168°14′52″ |
| C-D | 168°14′52″ + 180° + 89°16′53″ − 360° | 77°31′45″ |
| D-E | 77°31′45″ + 180° + 96°36′05″ | 354°07′50″ |
| E-T2 | 354°07′50″ + 180° + 291°27′38″ − 720° | 105°35′28″ |
Computed FB of E-T2 = 105°35′28″; given (known) FB of E-T2 = 105°36′08″.
Step 2: Angular misclosure
The computed bearing is 40″ too small. This is only 8″ per angle for 5 angles, which is acceptable for a 20″ theodolite (the permissible value with is about ). The error is distributed equally among the 5 angles.
Step 3: Adjustment
Total correction = +0°00′40″ (added to the computed bearing of the last line). It is distributed equally over the 5 observed angles: +0°00′40″ / 5 = +0°00′08″ per angle. The correction to a line is +0°00′08″ multiplied by the number of angles used to reach it.
| Line | Computed FB | Correction | Corrected FB | Corrected BB |
|---|---|---|---|---|
| T1-A | 339°09′21″ | 0 | 339°09′21″ | 159°09′21″ |
| A-B | 81°26′39″ | +0°00′08″ | 81°26′47″ | 261°26′47″ |
| B-C | 168°14′52″ | +0°00′16″ | 168°15′08″ | 348°15′08″ |
| C-D | 77°31′45″ | +0°00′24″ | 77°32′09″ | 257°32′09″ |
| D-E | 354°07′50″ | +0°00′32″ | 354°08′22″ | 174°08′22″ |
| E-T2 | 105°35′28″ | +0°00′40″ | 105°36′08″ | 285°36′08″ |
Check: the corrected FB of the last line equals the given value 105°36′08″.
Answer: angle misclosure = 40″ (computed ET2 = 105°35′28″, adjusted ET2 = 105°36′08″). Adjustment = +8″ per angle (bearing corrections +8″, +16″, +24″, +32″, +40″). Adjusted bearings: T1A 339°09′21″, AB 81°26′47″, BC 168°15′08″, CD 77°32′09″, DE 354°08′22″, ET2 105°36′08″.
Note: the adjusted angles are the observed angles plus 8″ each; the correction is added to each angle to the right because the computed bearing is too small.
✓ Answer checked by Claude Opus 5.5 (high effort)
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