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Link traverse ABCDEF, right turn angles

Short answer

Misclosure +80″ exceeds the permissible 40″, so observations are not correct. Corrected fore bearings: AB 61°06′00″, BC 334°13′10″, CD 358°28′00″, DE 291°18′40″, EF 202°17′20″ (back bearing 22°17′20″ matches observed).

The fore bearing of line AB of a link traverse ABCDEF is 61°06′00″. The right turn angles at stations with theodolite were observed as follows: ∠B = 93°06′50″, ∠C = -204°14′30″, ∠D = -112°50′20″ and ∠E = 90°58′20″. If the BB of the last line observed was 22°17′20″, check whether the observations for angles are correct or not. If not, compute the correct bearings of all lines. The value of C is 20″.

Right-turn angles (measured clockwise from the back station to the forward station) are always positive, between 0∘0^\circ and 360∘360^\circ. The "−" signs printed before ∠C and ∠D are therefore read as dashes, so ∠C = 204°14′30″ and ∠D = 112°50′20″. (If they are treated as negative angles, the computed bearing of the last line misses the observed one by 85°49′, which is impossible for a real traverse; with the angles read as positive, the misclosure is only 1′20″, which confirms this reading.)

Angles used: B = 93°06′50″, C = 204°14′30″, D = 112°50′20″, E = 90°58′20″.

Rule (angles to the right): FB of next line=FB of previous line+180∘+angle to the right\text{FB of next line} = \text{FB of previous line} + 180^\circ + \text{angle to the right} (add or subtract 360∘360^\circ to bring the result between 0∘0^\circ and 360∘360^\circ).

Step 1: Bearings computed from the observed angles

LineWorkingComputed FB
ABgiven61°06′00″
BC61°06′00″ + 180° + 93°06′50″334°12′50″
CD334°12′50″ + 180° + 204°14′30″ − 360°358°27′20″
DE358°27′20″ + 180° + 112°50′20″ − 360°291°17′40″
EF291°17′40″ + 180° + 90°58′20″ − 360°202°16′00″

Computed FB of EF = 202°16′00″, so the computed BB of EF = 22°16′00″. The observed BB of EF is 22°17′20″ (observed FB = 202°17′20″).

(Check: sum of angles = 501°10′00″; 61°06′00″ + 501°10′00″ + 4 × 180° = 1282°16′00″, and 1282°16′00″ − 3 × 360° = 202°16′00″.)

Step 2: Angular misclosure

Misclosure=observed−computed=22∘17′20′′−22∘16′00′′=+1′20′′=+80′′\text{Misclosure} = \text{observed} - \text{computed} = 22^\circ 17' 20'' - 22^\circ 16' 00'' = +1' 20'' = +80''

Permissible misclosure =Cn=20′′4=40′′= C\sqrt{n} = 20''\sqrt{4} = 40''.

Since 80′′>40′′80'' > 40'', the angle observations are not correct (the error is outside the allowable limit). Strictly, the angles should be re-observed; for the correction asked in the question, the error is distributed equally over the four angles: +80′′/4=+20′′+80''/4 = +20'' per angle.

Step 3: Corrected bearings

The correction to a line is +20″ multiplied by the number of angles used to reach it.

LineComputed FBCorrectionCorrected FBCorrected BB
AB61°06′00″061°06′00″241°06′00″
BC334°12′50″+20″334°13′10″154°13′10″
CD358°27′20″+40″358°28′00″178°28′00″
DE291°17′40″+60″291°18′40″111°18′40″
EF202°16′00″+80″202°17′20″22°17′20″

Check: the corrected BB of the last line equals the observed value 22°17′20″.

Corrected angles: B = 93°07′10″, C = 204°14′50″, D = 112°50′40″, E = 90°58′40″.

Answer: misclosure = +80″, which exceeds the permissible 40″, so the observations are not correct. Corrected bearings (FB): AB 61°06′00″, BC 334°13′10″, CD 358°28′00″, DE 291°18′40″, EF 202°17′20″ (BB of EF = 22°17′20″).

✓ Answer checked by Claude Opus 5.5 (high effort)

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