- Asked 2/31
- 2074 Chaitra · 8 marks
Open traverse ABCDEFGH, deflection angles
Short answer
Misclosure −1°00′, observations are incorrect. Corrected bearings: AB 81°45′, BC 107°05′, CD 69°10′, DE 114°15′, EF 58°35′, FG 343°10′, GH 63°00′.
The fore bearing of line AB of an open traverse ABCDEFGH is 81°45′. The deflection angles between the lines were measured with a theodolite and were as follows: 25°30′ (R) at B, 37°45′ (L) at C, 45°15′ (R) at D, 55°30′ (L) at E, 75°15′ (L) at F and 80°00′ (R) at G. If the FB of the last line observed was 63°00′, check whether the observations for deflection angles are correct or not. If not, compute the correct bearings of all the lines.
The bearing of the last line, computed from the first bearing and the observed deflection angles, is compared with its observed bearing. Right deflection is taken as and left as .
Rule (deflection angles): , with for a right deflection and for a left deflection.
Step 1: Bearings computed from the observed angles
| Line | Working | Computed FB |
|---|---|---|
| AB | given | 81°45′ |
| BC | 81°45′ + 25°30′ | 107°15′ |
| CD | 107°15′ − 37°45′ | 69°30′ |
| DE | 69°30′ + 45°15′ | 114°45′ |
| EF | 114°45′ − 55°30′ | 59°15′ |
| FG | 59°15′ − 75°15′ + 360° | 344°00′ |
| GH | 344°00′ + 80°00′ − 360° | 64°00′ |
Computed FB of GH = 64°00′; observed FB of GH = 63°00′ (given directly).
Step 2: Angular misclosure
The computed and observed bearings do not agree, so the deflection angles are not correct. The misclosure of −1°00′ is distributed equally among the 6 angles (−10′ each).
Step 3: Adjustment
Correction per angle = −1°00′ / 6 = −0°10′. The correction to a line is −0°10′ multiplied by the number of angles used to reach it.
| Line | Computed FB | Correction | Corrected FB | Corrected BB |
|---|---|---|---|---|
| AB | 81°45′ | 0 | 81°45′ | 261°45′ |
| BC | 107°15′ | −0°10′ | 107°05′ | 287°05′ |
| CD | 69°30′ | −0°20′ | 69°10′ | 249°10′ |
| DE | 114°45′ | −0°30′ | 114°15′ | 294°15′ |
| EF | 59°15′ | −0°40′ | 58°35′ | 238°35′ |
| FG | 344°00′ | −0°50′ | 343°10′ | 163°10′ |
| GH | 64°00′ | −1°00′ | 63°00′ | 243°00′ |
Check: the corrected FB of the last line equals the observed value 63°00′.
Corrected deflection angles
The correction of −10′ is applied to each signed deflection angle (right , left ), so a right deflection becomes 10′ smaller and a left deflection 10′ larger.
| Station | Observed deflection | Correction (to signed angle) | Corrected deflection |
|---|---|---|---|
| B | 25°30′ (R) | −0°10′ | 25°20′ (R) |
| C | 37°45′ (L) | −0°10′ | 37°55′ (L) |
| D | 45°15′ (R) | −0°10′ | 45°05′ (R) |
| E | 55°30′ (L) | −0°10′ | 55°40′ (L) |
| F | 75°15′ (L) | −0°10′ | 75°25′ (L) |
| G | 80°00′ (R) | −0°10′ | 79°50′ (R) |
Answer: misclosure = −1°00′ (observations not correct). Corrected bearings: AB 81°45′, BC 107°05′, CD 69°10′, DE 114°15′, EF 58°35′, FG 343°10′, GH 63°00′.
✓ Answer checked by Claude Opus 5.5 (high effort)
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