- Asked 2/31
- 2079 Bhadra · 8 marks
Open traverse ABCDEFG, deflection angles
Short answer
Misclosure +1°00′, observations incorrect. Corrected bearings: AB 40°45′, BC 67°34′, CD 1°01′, DE 22°09′, EF 56°15′, FG 29°33′. Corrected deflection angles: B 26°49′ R, C 66°33′ L, D 21°08′ R, E 34°06′ R, F 26°42′ L.
The FB of line AB of an open traverse ABCDEFG is 40°45′. The deflection angles between the lines were measured with a theodolite and were as follows: 26°37′ (R) at B, 66°45′ (L) at C, 20°56′ (R) at D, 33°54′ (R) at E and 26°54′ (L) at F. If the BB of the last line FG observed was 209°33′, check whether the observations for deflection angles were correct or not. If not, compute the correct bearings of all the lines and the correct deflection angles.
For an open traverse whose last line has been observed independently, the bearing of the last line computed through the deflection angles must agree with the observed bearing. Right deflection is taken as and left as .
Rule (deflection angles): , with for a right deflection and for a left deflection.
Step 1: Bearings computed from the observed angles
| Line | Working | Computed FB |
|---|---|---|
| AB | given | 40°45′ |
| BC | 40°45′ + 26°37′ | 67°22′ |
| CD | 67°22′ − 66°45′ | 0°37′ |
| DE | 0°37′ + 20°56′ | 21°33′ |
| EF | 21°33′ + 33°54′ | 55°27′ |
| FG | 55°27′ − 26°54′ | 28°33′ |
Computed FB of FG = 28°33′. The observed back bearing of FG is 209°33′, so its observed FB is 209°33′ − 180° = 29°33′.
Step 2: Angular misclosure
The computed and observed bearings do not agree, so the observations of the deflection angles are not correct. The misclosure of +1°00′ is distributed equally among the 5 angles (+12′ each).
Step 3: Adjustment
Correction per angle = +1°00′ / 5 = +0°12′. The correction to a line is +0°12′ multiplied by the number of angles used to reach it.
| Line | Computed FB | Correction | Corrected FB | Corrected BB |
|---|---|---|---|---|
| AB | 40°45′ | 0 | 40°45′ | 220°45′ |
| BC | 67°22′ | +0°12′ | 67°34′ | 247°34′ |
| CD | 0°37′ | +0°24′ | 1°01′ | 181°01′ |
| DE | 21°33′ | +0°36′ | 22°09′ | 202°09′ |
| EF | 55°27′ | +0°48′ | 56°15′ | 236°15′ |
| FG | 28°33′ | +1°00′ | 29°33′ | 209°33′ |
Check: the corrected BB of the last line equals the observed value 209°33′.
Corrected deflection angles
The correction of +12′ is applied to each signed deflection angle (right , left ), so a right deflection becomes 12′ larger and a left deflection 12′ smaller.
| Station | Observed deflection | Correction (to signed angle) | Corrected deflection |
|---|---|---|---|
| B | 26°37′ (R) | +0°12′ | 26°49′ (R) |
| C | 66°45′ (L) | +0°12′ | 66°33′ (L) |
| D | 20°56′ (R) | +0°12′ | 21°08′ (R) |
| E | 33°54′ (R) | +0°12′ | 34°06′ (R) |
| F | 26°54′ (L) | +0°12′ | 26°42′ (L) |
Answer: misclosure = +1°00′ (observations not correct). Corrected bearings: AB 40°45′, BC 67°34′, CD 1°01′, DE 22°09′, EF 56°15′, FG 29°33′. Corrected deflection angles: B 26°49′ R, C 66°33′ L, D 21°08′ R, E 34°06′ R, F 26°42′ L.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Open traverse ABCDEFGH, deflection angles · Surveying I, chapter 4 · asked 2×
- Angular misclosure, link traverse ABCDEFG · Surveying I, chapter 4
- Link traverse ABCDEF, last line 108°05′40″ · Surveying I, chapter 4 · asked 3×
- Link traverse ABCDEF, right turn angles · Surveying I, chapter 4 · asked 3×
- Interior angles and bearings, closed traverse ABCD · Surveying I, chapter 4
- Theodolite traverse ABCDA with missing VCR (68°30′10″) · Surveying I, chapter 7
- Local attraction, bearings AB 305°00′ (EA 45°) · Surveying I, chapter 4 · asked 2×
- Heap sort on 37, 33, 26, 92, ... · Data Structure and Algorithm, chapter 7
- Design: 230 m head plant, 45 km line · Power Plant Design, chapter 4 · asked 12×
- AVL tree for 10 20 30 50 45 40 8 5 3 · Data Structure and Algorithm, chapter 6
- Every RE has NFA; ε-NFA for bb(a∪b)*ab · Theory of Computation, chapter 2