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Adjusted angles and bearings, angles to the left

Short answer

Angular misclosure +0.8', distributed as -0.2' per angle. Adjusted angles: A 208°07.4', B 101°34.9', C 89°05.1', D 17°11.7'. Adjusted bearings: AB 26°10.2', BC 104°35.3', CD 195°30.2', DX 358°18.5'.

For the traverse of measured angles (angle to the left) given in the table below, compute the adjusted angles and bearings to the nearest 0.1′.

StationMeasured angles
A208° 7.6′
B101° 35.1′
C89° 05.3′
D17° 11.9′

Known bearings: Line AW = 234° 17.6′; Line DX = 358° 18.5′.

The traverse starts on the known line AW and ends on the known line DX, so the observed angles can be checked and adjusted.

Rule for angles measured to the left (counter-clockwise from the back line to the forward line):

Bearing of forward line=Bearing of back line−angle to the left\text{Bearing of forward line} = \text{Bearing of back line} - \text{angle to the left}

where the back line is the line from the station towards the previous station. The back line at the next station is the forward line ±180∘\pm 180^\circ.

Step 1: Compute the bearings from the observed angles

StationBack line bearingAngle (left)Bearing of forward line
AAW = 234° 17.6′208° 07.6′AB = 26° 10.0′
BBA = 206° 10.0′101° 35.1′BC = 104° 34.9′
CCB = 284° 34.9′89° 05.3′CD = 195° 29.6′
DDC = 15° 29.6′17° 11.9′DX = 358° 17.7′ (computed)

Step 2: Angular misclosure

Known bearing of DX = 358° 18.5′; computed = 358° 17.7′.

Misclosure=358∘18.5′−358∘17.7′=+0.8′\text{Misclosure} = 358^\circ 18.5' - 358^\circ 17.7' = +0.8'

To raise the computed bearing by 0.8′, the angles to the left must be reduced. There are 4 angles, so the correction is −0.8′/4=−0.2′-0.8'/4 = -0.2' per angle.

Step 3: Adjusted angles and bearings

StationObserved angleCorrectionAdjusted angleAdjusted bearing of forward line
A208° 07.6′−0.2′208° 07.4′AB = 26° 10.2′
B101° 35.1′−0.2′101° 34.9′BC = 104° 35.3′
C89° 05.3′−0.2′89° 05.1′CD = 195° 30.2′
D17° 11.9′−0.2′17° 11.7′DX = 358° 18.5′ ✓

Check: the bearing of DX obtained from the adjusted angles equals the known 358° 18.5′.

Answer: adjusted angles A = 208° 07.4′, B = 101° 34.9′, C = 89° 05.1′, D = 17° 11.7′; adjusted bearings AB = 26° 10.2′, BC = 104° 35.3′, CD = 195° 30.2′, DX = 358° 18.5′.

✓ Answer checked by Claude Opus 5.5 (high effort)

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