- 2061 Baisakh · 10 marks
Adjusted angles and bearings, angles to the left
Short answer
Angular misclosure +0.8', distributed as -0.2' per angle. Adjusted angles: A 208°07.4', B 101°34.9', C 89°05.1', D 17°11.7'. Adjusted bearings: AB 26°10.2', BC 104°35.3', CD 195°30.2', DX 358°18.5'.
For the traverse of measured angles (angle to the left) given in the table below, compute the adjusted angles and bearings to the nearest 0.1′.
| Station | Measured angles |
|---|---|
| A | 208° 7.6′ |
| B | 101° 35.1′ |
| C | 89° 05.3′ |
| D | 17° 11.9′ |
Known bearings: Line AW = 234° 17.6′; Line DX = 358° 18.5′.
The traverse starts on the known line AW and ends on the known line DX, so the observed angles can be checked and adjusted.
Rule for angles measured to the left (counter-clockwise from the back line to the forward line):
where the back line is the line from the station towards the previous station. The back line at the next station is the forward line .
Step 1: Compute the bearings from the observed angles
| Station | Back line bearing | Angle (left) | Bearing of forward line |
|---|---|---|---|
| A | AW = 234° 17.6′ | 208° 07.6′ | AB = 26° 10.0′ |
| B | BA = 206° 10.0′ | 101° 35.1′ | BC = 104° 34.9′ |
| C | CB = 284° 34.9′ | 89° 05.3′ | CD = 195° 29.6′ |
| D | DC = 15° 29.6′ | 17° 11.9′ | DX = 358° 17.7′ (computed) |
Step 2: Angular misclosure
Known bearing of DX = 358° 18.5′; computed = 358° 17.7′.
To raise the computed bearing by 0.8′, the angles to the left must be reduced. There are 4 angles, so the correction is per angle.
Step 3: Adjusted angles and bearings
| Station | Observed angle | Correction | Adjusted angle | Adjusted bearing of forward line |
|---|---|---|---|---|
| A | 208° 07.6′ | −0.2′ | 208° 07.4′ | AB = 26° 10.2′ |
| B | 101° 35.1′ | −0.2′ | 101° 34.9′ | BC = 104° 35.3′ |
| C | 89° 05.3′ | −0.2′ | 89° 05.1′ | CD = 195° 30.2′ |
| D | 17° 11.9′ | −0.2′ | 17° 11.7′ | DX = 358° 18.5′ ✓ |
Check: the bearing of DX obtained from the adjusted angles equals the known 358° 18.5′.
Answer: adjusted angles A = 208° 07.4′, B = 101° 34.9′, C = 89° 05.1′, D = 17° 11.7′; adjusted bearings AB = 26° 10.2′, BC = 104° 35.3′, CD = 195° 30.2′, DX = 358° 18.5′.
✓ Answer checked by Claude Opus 5.5 (high effort)
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