- 2064 Jestha · 10 marks
Horizontal angles from field notes, triangle ABC
Short answer
Mean angles from two-face readings: A = 30°00′05″, B = 59°59′55″, C = 90°00′02.5″. Sum 180°00′02.5″, excess +2.5″; equal correction -0.83″ gives A = 30°00′04.17″, B = 59°59′54.17″, C = 90°00′01.67″.
The following are field notes of theodolite survey. Compute horizontal angles and apply check.
| Station | Sighted to | Direct (D M S) | Reverse (D M S) |
|---|---|---|---|
| A | C | 0 00 10 | 180 00 00 |
| B | 30 00 20 | 210 00 00 | |
| B | A | 0 00 00 | 180 00 20 |
| C | 60 00 00 | 240 00 10 | |
| C | B | 0 00 10 | 180 00 00 |
| A | 90 00 05 | 270 00 10 |
Check. The three stations A, B, C form a triangle, so the sum of the three angles must be 180°.
Method. For each target the mean direction is found from the two faces:
The angle at a station = mean direction of the forward station - mean direction of the back station. For a closed traverse of sides, the sum of the interior angles must be ; the difference is the angular error, which is distributed equally among the angles (the angles are measured with the same instrument and care).
Field book and mean angles
| Inst. stn | Sighted to | Face L | Face R | Mean direction | Mean angle |
|---|---|---|---|---|---|
| A | C | 0 00 10 | 180 00 00 | 0°00′05″ | |
| B | 30 00 20 | 210 00 00 | 30°00′10″ | 30°00′05″ | |
| B | A | 0 00 00 | 180 00 20 | 0°00′10″ | |
| C | 60 00 00 | 240 00 10 | 60°00′05″ | 59°59′55″ | |
| C | B | 0 00 10 | 180 00 00 | 0°00′05″ | |
| A | 90 00 05 | 270 00 10 | 90°00′07.5″ | 90°00′02.5″ |
Check and adjustment
Required sum = = 180°00′00″. Observed sum = 180°00′02.5″. Angular error = 180°00′02.5″ - 180°00′00″ = +0°00′02.5″. Correction per angle = -0°00′00.83″ (equal for all 3 angles).
| Angle at | Mean angle | Correction | Corrected angle |
|---|---|---|---|
| A | 30°00′05″ | -0°00′00.83″ | 30°00′04.17″ |
| B | 59°59′55″ | -0°00′00.83″ | 59°59′54.17″ |
| C | 90°00′02.5″ | -0°00′00.83″ | 90°00′01.67″ |
| Sum | 180°00′02.5″ | -0°00′02.5″ | 180°00′00″ |
Answer: corrected horizontal angles: A = 30°00′04.17″, B = 59°59′54.17″, C = 90°00′01.67″.
✓ Answer checked by Claude Opus 5.5 (high effort)
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