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Suspension bridge triangle ABC; span AB

Short answer

Triangle closure error −1′25″ distributed equally; corrected angles A=54°38′28.33″, B=89°21′23.33″, C=36°00′08.33″. Span AB by sine rule: AB = 58.232 × sin C / sin A = 41.972 m.

During the survey of a suspension bridge the following observations were made in triangle ABC. AB is the bridge axis. The least count of the instrument is 01′00″.

Inst. StationSighted toHCR Face LeftHCR Face Right
AB0°00′00″180°00′20″
C54°38′20″234°38′00″
BC0°00′00″179°59′50″
A89°20′40″269°21′00″
CA0°00′00″180°00′00″
B36°01′00″215°58′20″

Compute the angles by mean direction method and correct them if necessary. If the length of line BC is 58.232 m, find the span of bridge axis AB.

Method. Mean directions are obtained from the two faces, angles from differences of directions, the triangle sum is checked against 180°, the error is distributed equally, and the side AB is then found by the sine rule.

Inst. stnSighted toFace LFace RMean directionAngle
AB0°00′00″180°00′20″0°00′10″
C54°38′20″234°38′00″54°38′10″A = 54°38′00″
BC0°00′00″179°59′50″359°59′55″
A89°20′40″269°21′00″89°20′50″B = 89°20′55″
CA0°00′00″180°00′00″0°00′00″
B36°01′00″215°58′20″35°59′40″C = 35°59′40″

Check and correction

Sum of angles = 179°58′35″; required = 180°00′00″; error = -0°01′25″ (sum is less than 180°). The permissible error is about the least count times 3\sqrt{3} = 1′ × 1.73 ≈ 1′44″, so the error is acceptable and is distributed equally: correction = +0°00′28.33″ per angle.

AngleObservedCorrectionCorrected
A54°38′00″+0°00′28.33″54°38′28.33″
B89°20′55″+0°00′28.33″89°21′23.33″
C35°59′40″+0°00′28.33″36°00′08.33″
Sum179°58′35″+0°01′25″180°00′00″

Span AB

In triangle ABC, the side AB is opposite to the angle C and BC is opposite to angle A.

ABsin⁡C=BCsin⁡AAB=BC sin⁡Csin⁡A=58.232×sin⁡36°00′08.33″sin⁡54°38′28.33″=41.972 m\begin{aligned} \frac{AB}{\sin C} &= \frac{BC}{\sin A}\\ AB &= BC\,\frac{\sin C}{\sin A} = 58.232 \times \frac{\sin 36°00′08.33″}{\sin 54°38′28.33″} = 41.972\ \text{m} \end{aligned}

Answer: corrected angles A = 54°38′28.33″, B = 89°21′23.33″, C = 36°00′08.33″; span of the bridge AB = 41.972 m (about 41.97 m, since the instrument reads only to 1′).

✓ Answer checked by Claude Opus 5.5 (high effort)

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