- 2072 Chaitra · 7 marks
Bipolar DAC output and 3-bit transfer curve
Short answer
Vo = Vref(2D/2^n − 1). For 3-bit: D ranges 0–7, Vo steps from −Vref to +0.75 Vref with zero at D=4 (100). Transfer curve is a staircase crossing zero at mid‑code, demonstrating bipolar output.
Derive the expression for output voltage in Bipolar type Digital to Analog converter (DAC). Draw the transfer curve for digital input and analog output for 3 bit bipolar type DAC.
A bipolar DAC produces both positive and negative output voltages. It adds a constant offset current equal to half of full scale, with opposite sign, to the current of a normal R-2R DAC.
Circuit
Vref -->[ R-2R ladder ]--I_D----+
| Rf=2R
-Vref -----[ 2R ]----I_os------+--/\/\/--+
| |
(-)\ |
>-------+--> Vo
(+)/
GND
Derivation
- The R-2R ladder (current mode) sends this current into the virtual ground:
I_D = (Vref/R)(b(n−1)/2 + b(n−2)/4 + … + b0/2ⁿ)
= (Vref/R) · D/2ⁿ
- The offset branch from −Vref through 2R gives:
I_os = −Vref/(2R)
- The inverting summer output with Rf = 2R:
Vo = −Rf (I_D + I_os)
= −2R [ (Vref/R)(D/2ⁿ) − Vref/(2R) ]
= −Vref (2D/2ⁿ − 1)
Taking the polarity after an output inverter (or reversed references), the standard bipolar (offset binary) result is:
Vo = Vref (2D/2ⁿ − 1) = Vref (D − 2ⁿ⁻¹) / 2ⁿ⁻¹
- D = 0 gives −Vref
- D = 2ⁿ⁻¹ (MSB only) gives 0
- D = 2ⁿ − 1 gives Vref(1 − 2/2ⁿ)
Step size = 2Vref/2ⁿ.
Transfer curve for 3-bit bipolar DAC (n = 3)
Vo = Vref(2D/8 − 1), step = Vref/4.
| Input | D | Vo / Vref |
|---|---|---|
| 000 | 0 | −1.00 |
| 001 | 1 | −0.75 |
| 010 | 2 | −0.50 |
| 011 | 3 | −0.25 |
| 100 | 4 | 0 |
| 101 | 5 | +0.25 |
| 110 | 6 | +0.50 |
| 111 | 7 | +0.75 |
Vo/Vref
+0.75 | +---
+0.50 | +---+
+0.25 | +---+
0.00 |----------------+---+-----------
-0.25 | +---+
-0.50 | +---+
-0.75 | +---+
-1.00 +----+
000 001 010 011 100 101 110 111
The staircase goes from −Vref at 000 up through zero at 100 to +0.75 Vref at 111. Zero output falls at mid-code, which shows the bipolar nature of the output.
✓ Answer checked by Claude Opus 5.5 (high effort)
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