- Asked 2/13
- 2071 Chaitra · 2+5 marks
- 2069 Chaitra · 2+5 marks
Choppers; single-phase full bridge inverter
Short answer
Choppers are DC-DC converters that vary average output by high-frequency switching (Vo = k·Vs). A single-phase full-bridge inverter uses four switches (S1–S4); alternately firing S1&S2 and S3&S4 produces a ±Vs square wave across the load. RMS output is Vs, fundamental component is 0.9Vs, and antiparallel diodes handle reactive energy.
What are choppers? Explain the working principle of single phase, full bridge inverter with necessary circuits and waveforms.
Choppers
A chopper is a static DC-to-DC converter that converts a fixed DC voltage into a variable DC voltage by switching a semiconductor device ON and OFF at high frequency. The average output is Vo = k·Vs (step-down), where k = Ton/T is the duty cycle. Choppers are used in DC motor drives, battery vehicles and SMPS.
Single-phase full-bridge inverter
A full-bridge inverter uses four switches (S1–S4, SCRs/IGBTs with antiparallel diodes D1–D4) and one DC source Vs to produce an AC square wave of ±Vs across the load.
+Vs
+---+-----------+
| | |
| S1 D1 S3 D3
| | LOAD |
| A---[ R ]---B
| | |
| S4 D4 S2 D2
| | |
+---+-----------+
0 (−)
Working:
- 0 < t < T/2: S1 and S2 are ON. Current flows +Vs → S1 → A → load → B → S2 → negative. vAB = +Vs.
- T/2 < t < T: S3 and S4 are ON. Current flows +Vs → S3 → B → load → A → S4 → negative. vAB = −Vs.
- Switches in the same leg (S1–S4 or S3–S2) are never ON together, or the supply would be short-circuited.
- With an RL load, current lags; when switches change over, the stored energy returns to the source through the diodes (D3, D4 or D1, D2) before the current reverses. These are feedback diodes.
Waveforms (resistive load):
gate S1,S2 |‾‾‾‾‾|_____|‾‾‾‾‾|_____
gate S3,S4 |_____|‾‾‾‾‾|_____|‾‾‾‾‾
0 T/2 T
vo +Vs +-----+ +-----+
| | | |
0 ---+-----+-----+-----+---> t
| | | |
−Vs +-----+ +---
Output relations:
- Output is a square wave of amplitude Vs (twice that of a half-bridge with the same supply).
- RMS output voltage Vo = Vs.
- Fourier series: vo = Σ (4Vs/nπ) sin nωt for n = 1, 3, 5, …; fundamental RMS = 4Vs/(√2·π) = 0.9·Vs.
- Frequency is set by the switching rate; output voltage can be varied by PWM.
✓ Answer checked by Claude Opus 5.5 (high effort)
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