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Circular core, current for 1 T air gap (mean length)

Short answer

The mmf is the sum of iron and air-gap contributions. For a 10 cm mean magnetic path (including 2 mm gap) and 600 turns, the current needed to produce 1 T is approximately 2.69 A.

A magnetic circuit consists of a circular iron core having mean length of 10 cm and cross-sectional area of 100 mm2^2. The air gap is 2 mm and the core has 600 turns of winding. Calculate the magnitude of current to be passed through the winding to produce air gap flux of 1 Tesla. Given μr=4000\mu_r = 4000.

Given: mean length of magnetic circuit =10= 10 cm (taken to include the gap), A=100A = 100 mm2=10−4^2 = 10^{-4} m2^2, lg=2l_g = 2 mm, N=600N = 600, Bg=1B_g = 1 T, μr=4000\mu_r = 4000.

Neglecting leakage and fringing, BB is 1 T in both iron and gap.

Path lengths

li=0.100−0.002=0.098 ml_i = 0.100 - 0.002 = 0.098\ \text{m}

Mmf

Fi=Bliμ0μr=0.0984π×10−7×4000=19.50 ATFg=Blgμ0=0.0024π×10−7=1591.5 ATF=1611.0 AT\begin{aligned} F_i &= \frac{B l_i}{\mu_0\mu_r} = \frac{0.098}{4\pi\times10^{-7}\times4000} = 19.50\ \text{AT} \\ F_g &= \frac{B l_g}{\mu_0} = \frac{0.002}{4\pi\times10^{-7}} = 1591.5\ \text{AT} \\ F &= 1611.0\ \text{AT} \end{aligned}

Current

I=1611.0600=2.685 AI = \frac{1611.0}{600} = 2.685\ \text{A}

If the 10 cm is taken as the iron length only (gap extra), Fi=19.9F_i = 19.9 AT and I=2.686I = 2.686 A, so the answer is the same to three figures.

Answer: I≈2.69I \approx 2.69 A

✓ Answer checked by Claude Opus 5.5 (high effort)

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