- 2074 Bhadra · 8 marks
DC current for ring core with 2 mm air gap
Short answer
Using mean diameter 4.5 cm, iron length 0.1394 m, area 7.854×10⁻⁵ m², flux density B = 0.3 mWb/area = 3.82 T. MMF for air gap 6079 AT, iron 212 AT, total 6291 AT. Required direct current I = 6291/1000 = 6.29 A.
A magnetic core consists of circular ring with outer diameter 5.5 cm and inner diameter 3.5 cm. The relative permeability of the iron is 2000. A radial airgap of 2 mm is cut in this core. Calculate the direct current that will be required in a coil of 1000 turns uniformly distributed around the core to produce a magnetic flux of 0.3 mWb in the airgap. Assume the magnetic leakage is negligible.
Assumption: the ring has a circular cross-section whose diameter equals the radial width, cm.
Dimensions
Flux density
Ampere-turns
Current
Answer: I ≈ 6.29 A (dc). (B = 3.82 T is beyond the saturation of real iron; the answer assumes μr stays 2000. If a square 1 cm × 1 cm section is assumed instead, A = 1 cm², B = 3 T and I ≈ 4.94 A.)
✓ Answer checked by Claude Opus 5.5 (high effort)
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