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Define slip; linear portion of T-S curve

Short answer

Slip is s = (Ns - Nr)/Ns, equal to 1 at standstill and 0 at synchronous speed; rated slip is 2-5%. The motor operates in the linear region because T is proportional to s when sX2 is negligible, giving stable speed, high efficiency and low rotor copper loss; beyond maximum torque operation is unstable.

Define slip. Why does the induction motor operate only in the linear portion of torque-slip characteristics?

Slip

Slip is the fractional difference between synchronous speed and rotor speed, expressed as a fraction or percentage of synchronous speed:

s=Ns−NrNss = \frac{N_s - N_r}{N_s}

Here Ns=120fPN_s = \frac{120f}{P} is the speed of the rotating magnetic field and NrN_r is the rotor speed. At standstill s=1s = 1; at synchronous speed s=0s = 0. At rated load it is about 2 to 5 %. The rotor frequency is fr=sff_r = sf.

Why only the linear portion is used

The torque-slip curve is nearly a straight line for small slip (from s=0s=0 to the slip at about full load) because sX2≪R2sX_2 \ll R_2, so

T≈3E22ωsR2 s  ∝  sT \approx \frac{3E_2^2}{\omega_s R_2}\,s \;\propto\; s
  • This region lies on the stable side of the maximum torque (s<sms < s_m). An increase in load slows the rotor a little, slip and torque increase, and the motor settles at a new steady speed.
  • Beyond the maximum torque (s>sms > s_m) the torque falls as slip increases, so any extra load makes the motor stall.
  • In the linear region the rotor copper loss (sPgsP_g) is small, so efficiency is high, and the speed is nearly constant.

✓ Answer checked by Claude Opus 5.5 (high effort)

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