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T-S characteristics and effect of rotor resistance

Short answer

Torque-slip curve rises linearly in low-slip stable region, peaks at sm = R2/X2, then falls. Starting torque occurs at s=1; maximum torque is independent of rotor resistance. Increasing rotor resistance shifts peak toward s=1 and increases starting torque up to Tmax.

Explain the torque-slip characteristics of a 3-phase induction motor, indicating the starting torque, maximum torque and the operating region. How does rotor resistance affect the torque-slip characteristics?

The torque-slip characteristic shows how the torque developed by a 3-phase induction motor varies with slip (from s=1s = 1 at standstill to s=0s = 0 at synchronous speed), at rated voltage and frequency.

Torque of a 3-phase induction motor at slip ss (per-phase equivalent):

T=3ωs⋅sE22R2R22+(sX2)2 N⋅mT = \frac{3}{\omega_s}\cdot\frac{sE_2^2R_2}{R_2^2 + (sX_2)^2}\ \text{N·m}

where E2E_2 and X2X_2 are the rotor emf and reactance per phase at standstill and ωs\omega_s is the synchronous speed in rad/s.

 Torque T
   |          Tmax
   |         .--*--.
   |  Tst   /   |   \          Operating
   |    *--'    |    \          region
   |            |     \___ ___ (stable)
   |            |     
   +------------+-----------+----> slip s
   1 (standstill) sm       0 (sync)

Regions of the curve

  1. Starting point (s=1s = 1): the torque is the starting torque TstT_{st}. Here the rotor reactance sX2sX_2 is large, so the rotor power factor is low and the torque is less than the maximum.
  2. Low-slip (operating) region (0<s<sm0 < s < s_m): the rotor reactance is small, so sX2≪R2sX_2\ll R_2 and T≈3sE22ωsR2∝sT\approx \dfrac{3sE_2^2}{\omega_sR_2}\propto s. The curve is almost a straight line. The motor works stably here: if the load rises, the speed falls slightly, slip increases and torque increases to meet it. The full-load slip is only about 2–5%.
  3. Maximum torque point (s=sms = s_m): the pull-out or breakdown torque TmaxT_{max} occurs at sm=R2/X2s_m = R_2/X_2 and has the value
Tmax=3E222ωsX2T_{max} = \frac{3E_2^2}{2\omega_sX_2}
  1. High-slip region (sm<s<1s_m < s < 1): torque decreases as slip increases because sX2sX_2 dominates (T∝1/sT\propto 1/s). This region is unstable for normal loads; if the load torque exceeds TmaxT_{max}, the motor stalls.

Effect of rotor resistance

TmaxT_{max} does not depend on R2R_2, but the slip at which it occurs does: sm=R2/X2s_m = R_2/X_2.

 T
 |      R2 low    R2 med    R2 high
 |      .-*-.     .-*-.      .-*-.
 |     /     \   /     \    /     \
 |    /       \ /       \  /       \
 +---+--------+---------+--+--------+--> s
  • Increasing R2R_2 (wound-rotor motor with external resistance) moves the peak toward higher slip (toward s=1s = 1). When R2=X2R_2 = X_2, sm=1s_m = 1 and maximum torque occurs at starting.
  • The starting torque increases (up to TmaxT_{max} when R2=X2R_2 = X_2; more resistance beyond that reduces it again) and the starting current falls (better rotor power factor).
  • The slope in the operating region becomes less steep, so the speed regulation worsens (more slip for the same torque), and the running efficiency falls due to I22R2I_2^2R_2 loss.
  • Hence external rotor resistance is used for starting and speed control in slip-ring motors, and then cut out for running.

✓ Answer checked by Claude Opus 5.5 (high effort)

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