- Asked 2/26
- 2073 Bhadra · 2 marks
- 2070 Bhadra · 2 marks
Conditions for plane failure
Short answer
Plane failure occurs when a discontinuity strikes nearly parallel to the slope face (±20°), dips out of the face at an angle less than the slope but greater than the friction angle, and is bounded laterally by release surfaces or a tension crack. On a stereonet, the plane's pole lies inside the daylight envelope and outside the friction circle.
What are the conditions for plane failure of a rock slope?
Plane failure is the sliding of a rock block along a single plane of weakness (joint, bedding or foliation) that daylights in the slope face. According to Hoek and Bray, it occurs when all these conditions are satisfied:
- Strike: the plane strikes parallel, or nearly parallel (within about ), to the slope face. That is, the dip directions of the plane and the slope differ by no more than about .
- Daylighting: the plane dips less steeply than the slope face, , so that the plane is exposed in the face.
- Friction: the dip of the plane is greater than its friction angle, , so that the block can slide under gravity.
- Release surfaces: the sliding block must be free at its sides, either through lateral release joints of negligible resistance or because the plane passes through a convex nose of the slope; a tension crack usually bounds it at the top.
crest tension crack
\ |
\ |__
face \ \ \ sliding plane
\ \ \ (dip psi_p)
\_____\_\___
Stereonet test: on a great-circle plot, the dip vector of the plane lies between the slope great circle and the friction circle, within about of the slope dip direction; equivalently, on a pole plot, the pole lies inside the daylight envelope and outside the friction circle. If , the slope is stable against plane sliding.
✓ Answer checked by Claude Opus 5.5 (high effort)
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