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Failure mode: HS 75/230, BP 68/045

Short answer

With phi=32°, kinematic tests reveal plane failure on J1 (dip 49° toward 215°, within 20° of face, >phi, <face angle), toppling on BP (steep, opposite direction, dip 68° >47° limit), and multiple wedge failures (J1-J2, J2-J3, J1-J3). Slope highly unstable; flatten to <45° and reinforce.

Suggest the possible mode of failure from the following figure. Hill slope (HS) 75°/230°; Bedding plane (BP) 68°/045°; Joint (J1) 49°/215°; Joint (J2) 55°/265°; Joint (J3) 65°/199°; Internal friction angle (ϕ) 32°. [Figure: stereonet showing HS, BP, J1, J2, J3]

Method (lower-hemisphere stereonet, equal-angle): plot the great circle of the slope face and of each discontinuity, draw the friction circle of radius ϕ\phi, and mark intersections of great circles. Then apply the kinematic tests below.

Data (dip/dip direction)

HS 75/230; BP 68/045; J1 49/215; J2 55/265; J3 65/199; ϕ=32∘\phi = 32^\circ.

Single planes

Plane (dip/dip dir)Diff. of dip dir from slopeDaylights (ψp<ψf\psi_p<\psi_f)ψp>ϕ\psi_p>\phiResult
BP (68/045)175°yesyesToppling
J1 (49/215)15°yesyesPlane failure
J2 (55/265)35°yesyesSafe
J3 (65/199)31°yesyesSafe

Intersections

PairIntersection plunge/trendFace apparent dip along trendResult
J1 x J248.4° / 227°75.0°Wedge failure
J1 x J332.1° / 272°70.2°Wedge failure
J2 x J354.0° / 249°74.2°Wedge failure

(The other 3 intersections plunge into the hill, away from the face, and cannot slide.)

Result

  • J1 dips 49∘49^\circ at 215°, only 15∘15^\circ from the face direction. 32∘<49∘<75∘32^\circ < 49^\circ < 75^\circ: plane failure along J1.
  • BP dips 68∘68^\circ at 045°, opposite to the face (230° - 180° = 050°) and steeper than 90∘−75∘+32∘=47∘90^\circ - 75^\circ + 32^\circ = 47^\circ: toppling failure.
  • J1 x J2, J2 x J3 (and marginally J1 x J3) intersect with plunges above 32∘32^\circ but below the face apparent dip: wedge failure is also possible because the face is very steep.

Conclusion: the main modes are plane failure along J1 and toppling of bedding slabs (BP), with secondary wedge sliding. The slope needs to be flattened to less than about 45∘45^\circ (J1 dip is 49∘49^\circ) and reinforced.

✓ Answer checked by Claude Opus 5.5 (high effort)

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