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Failure mode: HS 170/50, BP 160/42

Short answer

On the stereonet, the bedding plane (42/160) lies in the daylight envelope: its dip direction is only 10° from the slope, it daylights in the 50° face, and 42° exceeds the 26° friction angle. Failure mode is plane failure along the bedding plane. Reduce slope below 42° or use bolts and drainage.

Analyze the failure mode by using stereographic projection from the following data. H.S.: 170°/50°, B.P.: 160°/42°, Friction angle: 26°.

Method (lower-hemisphere stereonet, equal-angle): plot the great circle of the slope face and of each discontinuity, draw the friction circle of radius ϕ\phi, and mark intersections of great circles. Then apply the kinematic tests below.

Data (dip direction/dip)

Hill slope HS = 170°/50°, bedding plane BP = 160°/42°, ϕ=26∘\phi = 26^\circ. In dip/dip direction form: HS = 50/170, BP = 42/160.

Plane (dip/dip dir)Diff. of dip dir from slopeDaylights (ψp<ψf\psi_p<\psi_f)ψp>ϕ\psi_p>\phiResult
BP (42/160)10°yesyesPlane failure

Result

  • The dip directions differ by only 10∘10^\circ (within ±20∘\pm 20^\circ).
  • ψp=42∘<ψf=50∘\psi_p = 42^\circ < \psi_f = 50^\circ, so the bedding plane daylights in the face.
  • ψp=42∘>ϕ=26∘\psi_p = 42^\circ > \phi = 26^\circ.

On the stereonet, the dip vector of BP lies between the slope great circle and the friction circle (equivalently, its pole falls inside the daylight envelope). Possible mode of failure: plane failure (sliding along the bedding plane). It can be controlled by reducing the slope angle below 42∘42^\circ or by bolting and drainage.

✓ Answer checked by Claude Opus 5.5 (high effort)

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