- 2079 Asoj · 5 marks
Failure mode: HS 170/50, BP 160/42
Short answer
On the stereonet, the bedding plane (42/160) lies in the daylight envelope: its dip direction is only 10° from the slope, it daylights in the 50° face, and 42° exceeds the 26° friction angle. Failure mode is plane failure along the bedding plane. Reduce slope below 42° or use bolts and drainage.
Analyze the failure mode by using stereographic projection from the following data. H.S.: 170°/50°, B.P.: 160°/42°, Friction angle: 26°.
Method (lower-hemisphere stereonet, equal-angle): plot the great circle of the slope face and of each discontinuity, draw the friction circle of radius , and mark intersections of great circles. Then apply the kinematic tests below.
Data (dip direction/dip)
Hill slope HS = 170°/50°, bedding plane BP = 160°/42°, . In dip/dip direction form: HS = 50/170, BP = 42/160.
| Plane (dip/dip dir) | Diff. of dip dir from slope | Daylights () | Result | |
|---|---|---|---|---|
| BP (42/160) | 10° | yes | yes | Plane failure |
Result
- The dip directions differ by only (within ).
- , so the bedding plane daylights in the face.
- .
On the stereonet, the dip vector of BP lies between the slope great circle and the friction circle (equivalently, its pole falls inside the daylight envelope). Possible mode of failure: plane failure (sliding along the bedding plane). It can be controlled by reducing the slope angle below or by bolting and drainage.
✓ Answer checked by Claude Opus 5.5 (high effort)
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