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Circulation, vorticity and rotational flow

Short answer

Circulation Γ is the line integral of tangential velocity around a closed curve; vorticity ζ = ∇×V is twice the fluid angular velocity. In rotational flow ζ ≠ 0; in irrotational flow ζ =0, so ∂v/∂x = ∂u/∂y in 2D. For an elementary rectangle, dΓ = (∂v/∂x – ∂u/∂y)dxdy = ζ_z dA.

Define circulation and vorticity. Differentiate between rotational and irrotational flow. For a two-dimensional flow, show that the circulation around an elementary rectangle equals the vorticity multiplied by its area, and state the condition of irrotationality in terms of velocity components.

Definitions

Circulation Γ\Gamma is the line integral of the tangential velocity component around a closed curve:

Γ=∮V⃗⋅ds⃗\Gamma = \oint \vec V \cdot d\vec s

Vorticity ζ⃗\vec\zeta is twice the angular velocity of a fluid particle, ζ⃗=2ω⃗=∇×V⃗\vec\zeta = 2\vec\omega = \nabla \times \vec V. For 2D flow in the xyxy-plane:

ζz=∂v∂x−∂u∂y\zeta_z = \frac{\partial v}{\partial x} - \frac{\partial u}{\partial y}

Circulation round a rectangle

Take an element dx×dydx \times dy with velocity components uu, vv at the lower left corner, and go anticlockwise.

  • Bottom side (to the right): u dxu\,dx
  • Right side (up): (v+∂v∂xdx)dy\left(v + \dfrac{\partial v}{\partial x}dx\right)dy
  • Top side (to the left): −(u+∂u∂ydy)dx-\left(u + \dfrac{\partial u}{\partial y}dy\right)dx
  • Left side (down): −v dy-v\,dy

Adding:

dΓ=(∂v∂x−∂u∂y)dx dy=ζz dAd\Gamma = \left(\frac{\partial v}{\partial x} - \frac{\partial u}{\partial y}\right) dx\,dy = \zeta_z\, dA

So circulation per unit area equals vorticity. This is the basis of Stokes' theorem, Γ=∬ζ dA\Gamma = \iint \zeta\, dA.

Rotational and irrotational flow

BasisRotational flowIrrotational flow
Particle rotationParticles rotate about their own axesNo rotation of particles
Vorticity∇×V⃗≠0\nabla\times\vec V \neq 0∇×V⃗=0\nabla\times\vec V = 0
Condition in 2D∂v/∂x≠∂u/∂y\partial v/\partial x \neq \partial u/\partial y∂v/∂x=∂u/∂y\partial v/\partial x = \partial u/\partial y
Velocity potentialDoes not existExists
ExampleForced vortex, flow near a wall (boundary layer)Free vortex (except at centre), ideal-fluid flow

For irrotational flow a velocity potential ϕ\phi exists, with u=∂ϕ/∂xu = \partial\phi/\partial x and v=∂ϕ/∂yv = \partial\phi/\partial y.

✓ Answer checked by Claude Opus 5.5 (high effort)

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