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Conditions for critical flow in open channel

Short answer

Froude number Fr = 1, specific energy is minimum for the given discharge, and discharge is maximum for a given specific energy. Velocity head equals half the hydraulic depth; for rectangular channels, yc = (q²/g)^(1/3). The flow is unstable and small disturbances cannot travel upstream.

What are the different conditions to be fulfilled when flow is critical in open channel?

When flow in an open channel is critical, the following conditions are satisfied.

  1. Froude number equals unity: Fr=VgDh=1Fr=\dfrac{V}{\sqrt{gD_h}}=1, where Dh=A/TD_h=A/T is the hydraulic depth. Velocity equals the celerity of a small gravity wave.
  2. Specific energy is minimum for the given discharge: dEdy=0⇒Q2TgA3=1\dfrac{dE}{dy}=0\Rightarrow\dfrac{Q^2T}{gA^3}=1.
  3. Discharge is maximum for a given specific energy.
  4. Specific force (momentum function) is minimum for the given discharge.
  5. Velocity head equals half the hydraulic depth: V22g=A2T\dfrac{V^2}{2g}=\dfrac{A}{2T}. For rectangular channels, Vc22g=yc2\dfrac{V_c^2}{2g}=\dfrac{y_c}{2} and Emin=32ycE_{min}=\tfrac32y_c.
  6. Critical depth for a rectangular channel is yc=q2/g3y_c=\sqrt[3]{q^2/g} and for other sections is found from A3T=Q2g\dfrac{A^3}{T}=\dfrac{Q^2}{g} (section factor Z=Q/gZ=Q/\sqrt g).
  7. The slope of the channel equals the critical slope ScS_c (for uniform flow at critical depth): Sc=gn2DhR4/3S_c=\dfrac{gn^2D_h}{R^{4/3}} or gPcC2Tc\dfrac{g P_c}{C^2T_c}.
  8. The flow is unstable: the water surface is wavy and sensitive to small changes in energy or roughness, and the depth changes rapidly. The flow is at the boundary between subcritical and supercritical states.
  9. Disturbances (small waves) cannot travel upstream.

✓ Answer checked by Claude Opus 5.5 (high effort)

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