Skip to main content

Surface profiles on mild slope

Short answer

A mild slope has yₙ > yc (subcritical uniform flow). M1 curve (y > yₙ) rises downstream, asymptotic to NDL and horizontal at reservoir. M2 (yₙ > y > yc) falls downstream from NDL to CDL steeply. M3 (y < yc) rises downstream, meeting CDL steeply, often causing a hydraulic jump.

What is a mild slope? Justify analytically the nature of surface profiles (both upstream and downstream end) for mild slope.

Mild slope

A channel slope is mild when the normal depth is greater than the critical depth, yn>ycy_n > y_c (equivalently S0<ScS_0 < S_c). Uniform flow on it is subcritical.

Analysis

Use the dynamic equation in the wide-channel form

dydx=S0 1−(yn/y)10/31−(yc/y)3\frac{dy}{dx} = S_0\,\frac{1 - (y_n/y)^{10/3}}{1 - (y_c/y)^3}

with yn>ycy_n > y_c. The NDL and CDL divide the flow into three zones.

Zone 1: y>yn>ycy > y_n > y_c (M1 curve)

Numerator >0> 0, denominator >0> 0, so dy/dx>0dy/dx > 0 (depth increases downstream).

  • Upstream end: y→yny \to y_n, so dy/dx→0dy/dx \to 0. The curve is asymptotic to the NDL.
  • Downstream end: y→∞y \to \infty, so dy/dx→S0dy/dx \to S_0. The water surface becomes horizontal, as in a reservoir.
  • Backwater curve, caused by dams or weirs.

Zone 2: yn>y>ycy_n > y > y_c (M2 curve)

Numerator <0< 0, denominator >0> 0, so dy/dx<0dy/dx < 0 (depth falls downstream).

  • Upstream end: y→yny \to y_n, dy/dx→0dy/dx \to 0: asymptotic to the NDL.
  • Downstream end: y→ycy \to y_c, denominator →0\to 0, so dy/dx→−∞dy/dx \to -\infty: the curve meets the CDL at a steep angle.
  • Drawdown curve, as at a free overfall or a break to a steeper slope.

Zone 3: y<yc<yny < y_c < y_n (M3 curve)

Numerator <0< 0, denominator <0< 0, so dy/dx>0dy/dx > 0 (depth rises downstream).

  • Upstream end: starts from a control at small depth (e.g. below a gate).
  • Downstream end: y→ycy \to y_c, dy/dx→∞dy/dx \to \infty: the curve meets the CDL steeply, and in practice a hydraulic jump forms before it.
ProfileZonedy/dxdy/dxUpstream endDownstream end
M1y>yny > y_n++tangent to NDLhorizontal (S0S_0)
M2yn>y>ycy_n > y > y_c−-tangent to NDLsteeply meets CDL
M3y<ycy < y_c++from a controlsteeply meets CDL (jump)

✓ Answer checked by Claude Opus 5.5 (high effort)

All Hydraulics chapter 8 questions →