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Surface profiles on steep slope

Short answer

A steep slope has y_n < y_c (S0 > Sc). The S1 curve rises from a hydraulic jump at the CDL and becomes horizontal downstream; S2 falls steeply from a break in grade and asymptotes to the NDL; S3 rises from a control and also asymptotes to the NDL downstream.

What is a steep slope? Justify analytically the nature of surface profiles (both upstream and downstream end) for steep slope.

Steep slope

A channel slope is steep when the normal depth is smaller than the critical depth, yn<ycy_n < y_c (equivalently S0>ScS_0 > S_c). Uniform flow on it is supercritical.

Analysis

dydx=S0 1−(yn/y)10/31−(yc/y)3,yc>yn\frac{dy}{dx} = S_0\,\frac{1 - (y_n/y)^{10/3}}{1 - (y_c/y)^3},\qquad y_c > y_n

Zone 1: y>yc>yny > y_c > y_n (S1 curve)

Numerator >0> 0, denominator >0> 0, so dy/dx>0dy/dx > 0.

  • Upstream end: y→ycy \to y_c, dy/dx→∞dy/dx \to \infty. The curve meets the CDL at a steep angle, i.e. it begins at a hydraulic jump.
  • Downstream end: y→∞y \to \infty, dy/dx→S0dy/dx \to S_0; the surface becomes horizontal.
  • It is a backwater curve behind a dam, weir or sluice gate on a steep slope.

Zone 2: yc>y>yny_c > y > y_n (S2 curve)

Numerator >0> 0, denominator <0< 0, so dy/dx<0dy/dx < 0 (depth falls downstream).

  • Upstream end: y→ycy \to y_c, dy/dx→−∞dy/dx \to -\infty: steep departure from the CDL (e.g. from a break from mild to steep slope).
  • Downstream end: y→yny \to y_n, dy/dx→0dy/dx \to 0: asymptotic to the NDL.

Zone 3: y<yn<ycy < y_n < y_c (S3 curve)

Numerator <0< 0, denominator <0< 0, so dy/dx>0dy/dx > 0 (depth rises downstream).

  • Upstream end: starts at a control at small depth (below a sluice gate).
  • Downstream end: y→yny \to y_n, dy/dx→0dy/dx \to 0: asymptotic to the NDL.
ProfileZonedy/dxdy/dxUpstream endDownstream end
S1y>ycy > y_c++steeply meets CDL (jump)horizontal (S0S_0)
S2yc>y>yny_c > y > y_n−-steep from CDLtangent to NDL
S3y<yny < y_n++from a controltangent to NDL

✓ Answer checked by Claude Opus 5.5 (high effort)

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