Skip to main content

Define water hammer; continuity and momentum equations

Short answer

Water hammer is a pressure surge from sudden velocity change. Momentum equation: ∂V/∂t + g ∂H/∂x + fV|V|/(2D)=0. Continuity equation: ∂H/∂t + (c²/g) ∂V/∂x =0, with c as wave celerity.

Define water hammer and write down continuity equation and momentum equation for unsteady flow in pipe.

Water hammer

Water hammer is the rise and fall of pressure in a pipe caused by a sudden change of flow velocity, such as the quick closing or opening of a valve or turbine gate, or a pump failure. The kinetic energy of the moving water changes into elastic (strain) energy of the water and the pipe wall. A pressure wave travels along the pipe at celerity cc and is reflected at the ends. It may burst or collapse the pipe and causes a hammering noise.

Equation of motion (momentum / Euler's equation)

Newton's second law for a water element in a pipe of diameter DD, with xx along the pipe, velocity VV and piezometric head HH:

∂V∂t+V∂V∂x+g∂H∂x+fV∣V∣2D=0\frac{\partial V}{\partial t}+V\frac{\partial V}{\partial x}+g\frac{\partial H}{\partial x}+\frac{fV|V|}{2D}=0

For water hammer, the convective term V ∂V/∂xV\,\partial V/\partial x is small compared with ∂V/∂t\partial V/\partial t and is neglected:

∂V∂t+g∂H∂x+fV∣V∣2D=0\frac{\partial V}{\partial t}+g\frac{\partial H}{\partial x}+\frac{fV|V|}{2D}=0

Without friction, and for a horizontal pipe, this becomes the Euler equation 1ρ∂p∂x+∂V∂t=0\dfrac{1}{\rho}\dfrac{\partial p}{\partial x}+\dfrac{\partial V}{\partial t}=0.

Continuity equation

Mass conservation, including the compressibility of water (bulk modulus KK) and the elasticity of the pipe:

1ρdpdt+c2∂V∂x=0or∂H∂t+c2g∂V∂x=0\frac{1}{\rho}\frac{dp}{dt}+c^2\frac{\partial V}{\partial x}=0\quad\text{or}\quad \frac{\partial H}{\partial t}+\frac{c^2}{g}\frac{\partial V}{\partial x}=0

where c=K/ρ1+KD/(Et)c=\sqrt{\dfrac{K/\rho}{1+KD/(Et)}} is the wave celerity.

These two equations (momentum and continuity) are solved together, e.g. by the method of characteristics, to find HH and VV along the pipe at any time.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Hydraulics chapter 4 questions →