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Wheatstone bridge for strain gauges

Short answer

For four active arms, Vo = Vex/4(dR1/R - dR2/R + dR3/R - dR4/R), or Vex G/4(eps1 - eps2 + eps3 - eps4). Quarter bridge uses one active gauge, half bridge two, full bridge four; adjacent arms subtract and opposite arms add, giving temperature compensation.

Derive the output of a Wheatstone bridge with all four arms active. Hence explain the quarter-bridge, half-bridge and full-bridge arrangements for strain measurement and how temperature compensation is obtained.

A Wheatstone bridge converts the small resistance changes of strain gauges into a measurable voltage.

Bridge output

Four arms R1R_1 (between A and B), R2R_2 (B-C), R3R_3 (C-D), R4R_4 (D-A). The excitation VexV_{ex} is applied across A and C, and the output is measured between B and D.

          A
        /   \
      R1     R4
      /       \
     B         D     output V_o between B and D
      \       /
      R2     R3
        \   /
          C   (V_ex across A and C)
Vo=Vex[R1R1+R2−R4R3+R4]V_o = V_{ex}\left[\frac{R_1}{R_1 + R_2} - \frac{R_4}{R_3 + R_4}\right]

The bridge is balanced (Vo=0V_o = 0) when R1R3=R2R4R_1R_3 = R_2R_4.

Let each arm be RR initially and change by ΔRi\Delta R_i. For small changes:

Vo=Vex4[ΔR1R−ΔR2R+ΔR3R−ΔR4R]V_o = \frac{V_{ex}}{4}\left[\frac{\Delta R_1}{R} - \frac{\Delta R_2}{R} + \frac{\Delta R_3}{R} - \frac{\Delta R_4}{R}\right]

With ΔR/R=Gε\Delta R/R = G\varepsilon:

Vo=VexG4(ε1−ε2+ε3−ε4)V_o = \frac{V_{ex}G}{4}\left(\varepsilon_1 - \varepsilon_2 + \varepsilon_3 - \varepsilon_4\right)

Adjacent arms subtract and opposite arms add, which is the basis of compensation.

Arrangements

BridgeActive gaugesOutputRemarks
Quarter1VexGε/4V_{ex}G\varepsilon/4Dummy gauge in adjacent arm for temperature compensation
Half2 (one tension, one compression)VexGε/2V_{ex}G\varepsilon/2Bending beam; compensates temperature and axial load
Full4 (two tension, two compression)VexGεV_{ex}G\varepsilonHighest output, best compensation

Temperature compensation

Temperature changes the resistance of all gauges equally (the same ΔRT\Delta R_T). Because adjacent arms subtract, this common change cancels. In a quarter bridge a dummy gauge (same type, same temperature, mounted on unstrained material) is placed in the adjacent arm. In half and full bridges the active gauges act as each other's compensators. Strain from bending or axial load can similarly be separated by placing gauges in the correct arms (e.g. on top and bottom of a beam).

Comments

  • Output of a quarter bridge is slightly nonlinear for large ΔR/R\Delta R/R; half and full bridges are more linear.
  • A three-wire connection compensates the lead resistance.
  • Balancing and calibration (shunt calibration) are done before use.

✓ Answer checked by Claude Opus 5.5 (high effort)

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