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Line as source and sink of reactive power

Short answer

At loads below the surge impedance loading (SIL), the line’s shunt capacitance generates more reactive power than its series inductance absorbs, making it a net source. Above SIL, the inductance dominates, so the line becomes a sink. At SIL, net reactive power is zero.

Explain how a transmission line behaves as a source and sink of reactive power.

A transmission line has series inductance (which absorbs reactive power) and shunt capacitance (which generates reactive power). Whether the line as a whole is a source or a sink of VArs depends on which of the two is larger, and that depends on the load.

Reactive power generated and absorbed

For a line of length ll with reactance xx and susceptance bb per unit length, at voltage VV carrying current II:

Qgen≈V2b l,Qabs=I2x lQ_{gen} \approx V^2 b\,l,\qquad Q_{abs} = I^2 x\,l
  • QgenQ_{gen} depends on voltage, which is nearly constant, so it is almost fixed.
  • QabsQ_{abs} depends on I2I^2, so it rises with load.

Three cases

Using the surge impedance Zc=L/CZ_c = \sqrt{L/C} and surge impedance loading SIL=V2/ZcSIL = V^2/Z_c:

LoadingConditionLine behaves as
Light load (P<SILP < SIL)V2ωC>I2ωLV^2\omega C > I^2\omega LSource of VAr (capacitive); voltage rises along the line (Ferranti effect)
P=SILP = SIL (natural load)V2ωC=I2ωLV^2\omega C = I^2\omega LNeither; flat voltage profile, no net Q
Heavy load (P>SILP > SIL)I2ωL>V2ωCI^2\omega L > V^2\omega CSink of VAr (inductive); voltage drops along the line
 Q net from line
   + |\
     |  \   source (light load)
   0 +----*------------- P
     |    SIL  \
   - |           \  sink (heavy load)

Consequences

  • At light load, excess VArs raise receiving-end voltage; shunt reactors are switched in to absorb them.
  • At heavy load, the line absorbs VArs and voltage falls; shunt capacitors, SVCs or series capacitors supply VArs.
  • Long EHV lines and cables (high CC) are strong VAr sources at light load; short, heavily loaded lines are VAr sinks.

Example: a 400 kV line with Zc=400 ΩZ_c = 400\ \Omega has SIL = 400 MW. At 200 MW it supplies VArs to the system; at 600 MW it absorbs VArs.

✓ Answer checked by Claude Opus 5.5 (high effort)

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