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Parseval's relation; applications of FT

Short answer

Parseval's relation: ∫|x(t)|² dt = (1/2π)∫|X(ω)|² dω. Proof substitutes x*(t) via inverse FT, swaps integrals and identifies X(ω). Applications: 1) spectrum analysis and filter design; 2) LTI system analysis via Y(ω)=X(ω)H(ω); 3) communication (modulation, sampling).

State and prove Parseval's relation for finite energy signal. Describe any three applications of Fourier Transform.

Parseval's relation

Statement: For a finite-energy signal x(t)x(t) with Fourier transform X(jω)X(j\omega), the total energy computed in the time domain equals the total energy computed in the frequency domain:

E=∫−∞∞∣x(t)∣2 dt=12π∫−∞∞∣X(jω)∣2 dωE = \int_{-\infty}^{\infty} |x(t)|^2\,dt = \frac{1}{2\pi}\int_{-\infty}^{\infty} |X(j\omega)|^2\,d\omega

In terms of frequency ff (Hz), E=∫−∞∞∣X(f)∣2 dfE = \int_{-\infty}^{\infty}|X(f)|^2\,df. So ∣X(jω)∣2|X(j\omega)|^2 is the energy spectral density: it shows how the energy is distributed over frequency.

Proof: Start with the energy and write ∣x(t)∣2=x(t) x∗(t)|x(t)|^2 = x(t)\,x^*(t):

E=∫−∞∞x(t) x∗(t) dtE = \int_{-\infty}^{\infty} x(t)\,x^*(t)\,dt

Express x∗(t)x^*(t) using the inverse Fourier transform. Since x(t)=12π∫X(jω)ejωtdωx(t) = \frac{1}{2\pi}\int X(j\omega)e^{j\omega t}d\omega, taking the conjugate gives

x∗(t)=12π∫−∞∞X∗(jω) e−jωt dωx^*(t) = \frac{1}{2\pi}\int_{-\infty}^{\infty} X^*(j\omega)\,e^{-j\omega t}\,d\omega

Substitute and change the order of integration:

E=∫−∞∞x(t)[12π∫−∞∞X∗(jω)e−jωtdω]dt=12π∫−∞∞X∗(jω)[∫−∞∞x(t)e−jωtdt]dω=12π∫−∞∞X∗(jω) X(jω) dω=12π∫−∞∞∣X(jω)∣2 dω\begin{aligned} E &= \int_{-\infty}^{\infty} x(t)\left[\frac{1}{2\pi}\int_{-\infty}^{\infty} X^*(j\omega)e^{-j\omega t}d\omega\right]dt \\ &= \frac{1}{2\pi}\int_{-\infty}^{\infty} X^*(j\omega)\left[\int_{-\infty}^{\infty} x(t)e^{-j\omega t}dt\right]d\omega \\ &= \frac{1}{2\pi}\int_{-\infty}^{\infty} X^*(j\omega)\,X(j\omega)\,d\omega \\ &= \frac{1}{2\pi}\int_{-\infty}^{\infty} |X(j\omega)|^2\,d\omega \end{aligned}

The bracketed inner integral is exactly the definition of X(jω)X(j\omega). Hence the relation is proved.

Example: x(t)=e−atu(t)x(t) = e^{-at}u(t) has energy ∫0∞e−2atdt=12a\int_0^\infty e^{-2at}dt = \frac{1}{2a}. Its transform is 1a+jω\frac{1}{a+j\omega}, and 12π∫dωa2+ω2=12π⋅πa=12a\frac{1}{2\pi}\int \frac{d\omega}{a^2+\omega^2} = \frac{1}{2\pi}\cdot\frac{\pi}{a} = \frac{1}{2a}. Both sides agree.

Applications of Fourier transform

  1. Spectrum analysis and filter design: The FT shows which frequencies a signal contains. Filters (low-pass, band-pass, etc.) are designed and analysed using the frequency response H(jω)H(j\omega), which is the FT of the impulse response.
  2. LTI system analysis: Convolution in time becomes multiplication in frequency, Y(jω)=X(jω)H(jω)Y(j\omega) = X(j\omega)H(j\omega). This makes finding the output of LTI systems and solving linear differential equations much easier.
  3. Communication (modulation and sampling): Amplitude modulation, frequency-division multiplexing and the sampling theorem are all explained with the FT (modulation property shifts the spectrum to ω±ωc\omega \pm \omega_c).

Other uses: image and audio compression (JPEG, MP3), bandwidth calculation, and energy/power spectral analysis.

✓ Answer checked by Claude Opus 5.5 (high effort)

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