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Clogged drainage pipe soil volume

Short answer

Apply Darcy's law to find the soil plug length: L = k h A / Q = (10 × 20 × 0.02) / 0.15 = 26.67 m. Volume = A × L = 0.02 × 26.67 = 0.533 m³.

A drainage pipe is clogged with soil having coefficient of permeability 10 m/day. Due to clogging, the water level in the tank is raised to 20 m and the discharge is reduced to 0.15 m³/day. If the cross section of the pipe is 200 cm², what is the volume of soil in the pipe?

The soil plug in the pipe is a short column through which the tank water flows. Apply Darcy's law Q=k hL AQ = k\,\dfrac{h}{L}\,A to find its length LL.

Given

k=10k = 10 m/day, head h=20h = 20 m, Q=0.15Q = 0.15 m³/day, A=200A = 200 cm² =0.02= 0.02 m².

Length of soil plug

L=k h AQ=10×20×0.020.15=26.67 mL = \frac{k\,h\,A}{Q} = \frac{10 \times 20 \times 0.02}{0.15} = 26.67\ \text{m}

Volume of soil

V=A×L=0.02×26.67=0.533 m3V = A \times L = 0.02 \times 26.67 = 0.533\ \text{m}^3

Answer: The clogging soil is 26.67 m long, so its volume is about 0.5330.533 m³ (≈533\approx 533 litres).

The head is assumed to be fully lost through the plug.

✓ Answer checked by Claude Opus 5.5 (high effort)

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