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Surcharge 15 kPa, stresses at clay centre

Short answer

Before loading: total stress 207 kPa, pore pressure 90 kPa, effective stress 117 kPa. Immediately after: total 222 kPa, pore pressure 105 kPa, effective 117 kPa. Long after: total 222 kPa, pore pressure 90 kPa, effective 132 kPa.

A surcharge load of 15 kPa was applied on the ground surface having the soil profile as shown in the figure below. Consolidation settlement took place in the clay layer. A consolidation test was done for the clay layer and the following results were obtained: coefficient of consolidation, cvc_v = 3.25×10−73.25 \times 10^{-7} m²/s, compression index, CcC_c = 1.2 and coefficient of permeability, k = 3.5×10−93.5 \times 10^{-9} m/s. Assume that the consolidation of the clay layer is solely due to the change in stress at the center of the clay layer. Also, consider that there is no change in ground water level before and after the consolidation. Take γw\gamma_w = 10 kN/m³. [Figure: surcharge 15 kN/m²; sand layer γ = 18 kN/m³ from 0 to 2 m (water table at 2 m); sand layer γsat\gamma_{sat} = 20 kN/m³ from 2 to 8 m; clay layer γsat\gamma_{sat} = 17 kN/m³, e0e_0 = 2.4 from 8 to 14 m; sand layer below 14 m.] Determine the total, effective and pore water pressure at the center of the clay layer (i) before applying the surcharge load, (ii) immediately after applying the surcharge load and (iii) sufficiently long after applying the surcharge load.

Given: centre of clay is at 11 m depth (clay 8 m to 14 m). Water table at 2 m. γw=10\gamma_w = 10 kN/m³. Sand above the water table: 18 kN/m³; saturated sand: 20 kN/m³; clay: 17 kN/m³.

Total vertical stress at 11 m before loading:

σ0=18(2)+20(6)+17(3)=36+120+51=207 kPa\sigma_0 = 18(2) + 20(6) + 17(3) = 36 + 120 + 51 = 207\ \text{kPa}

Hydrostatic pore pressure: u0=10×(11−2)=90u_0 = 10 \times (11-2) = 90 kPa.

(i) Before applying the surcharge

Value (kPa)
Total stress σ\sigma207
Pore pressure uu90
Effective stress σ′=σ−u\sigma' = \sigma - u117

(ii) Immediately after applying the surcharge

The clay is saturated and the load is applied suddenly, so the entire 15 kPa is carried by the water (excess pore pressure Δu=15\Delta u = 15 kPa).

Value (kPa)
Total stress σ=207+15\sigma = 207 + 15222
Pore pressure u=90+15u = 90 + 15105
Effective stress σ′\sigma'117

(iii) Sufficiently long after loading (end of consolidation)

The excess pore pressure has fully dissipated (Δu=0\Delta u = 0), so the load is carried by the soil skeleton.

Value (kPa)
Total stress σ\sigma222
Pore pressure uu90
Effective stress σ′=222−90\sigma' = 222 - 90132

Answer: effective stress is 117 kPa at the start and rises to 132 kPa at the end of consolidation; pore pressure goes 90, then 105, then 90 kPa.

✓ Answer checked by Claude Opus 5.5 (high effort)

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