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Derive 1D primary consolidation settlement

Short answer

For a clay layer of thickness H and initial void ratio e0, primary consolidation settlement is Sc = Δe/(1+e0) H. Equivalently Sc = mv Δσ' H. For normally consolidated clay, Sc = Cc H/(1+e0) log10((σ0'+Δσ')/σ0').

Derive the general equation for the calculation of settlement from one-dimensional primary consolidation.

Consider a clay layer of thickness HH and initial void ratio e0e_0 under a stress increase Δσ′\Delta\sigma', so that the void ratio decreases by Δe\Delta e (one-dimensional compression, no lateral strain).

  before: Vs + Vv0 = 1 + e0     after: Vs + Vv = 1 + e0 - Δe
  |  H   |                      | H - ΔH |

For a unit volume of solids, the initial total volume is 1+e01 + e_0 and the reduction in volume is Δe\Delta e. Since the area is constant, the vertical strain equals the volumetric strain:

ΔHH=ΔVV=Δe1+e0\frac{\Delta H}{H} = \frac{\Delta V}{V} = \frac{\Delta e}{1+e_0} Sc=ΔH=Δe1+e0 H\boxed{S_c = \Delta H = \frac{\Delta e}{1+e_0}\,H}

In terms of the compressibility:

  • With av=ΔeΔσ′a_v = \dfrac{\Delta e}{\Delta\sigma'}:   Sc=av1+e0Δσ′ H=mv Δσ′ H\;S_c = \dfrac{a_v}{1+e_0}\Delta\sigma'\,H = m_v\,\Delta\sigma'\,H
  • With the compression index CcC_c (NC clay): Δe=Cclog⁡10σ0′+Δσ′σ0′\Delta e = C_c\log_{10}\dfrac{\sigma'_0 + \Delta\sigma'}{\sigma'_0}, so
Sc=Cc H1+e0log⁡10σ0′+Δσ′σ0′S_c = \frac{C_c\,H}{1+e_0}\log_{10}\frac{\sigma'_0 + \Delta\sigma'}{\sigma'_0}

where σ0′\sigma'_0 is the effective overburden pressure at the middle of the layer.

✓ Answer checked by Claude Opus 5.5 (high effort)

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