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Square root of time method for cv

Short answer

Taylor's square root of time method plots dial reading against √t, extends the initial straight line to get corrected d0, draws a second line from d0 with slope 1/1.15, and takes its intersection with the curve as √t90. Then cv = 0.848 Hdr^2 / t90.

With the help of a neat sketch, describe the method of determination of coefficient of consolidation by the square root of time method.

Taylor's square root of time method finds cvc_v from a consolidation test for a load increment, using the observed dial reading against t\sqrt t.

 dial                  
 reading |*.
         |  *.          straight line
    d0   |-----*.______  (extended to √t axis → d0 corrected)
         |       \ *  .
         |  line OB  \   *  *  *
         |  at 1.15x  C
         +-----------|--------------> √t
                    √t90

Procedure

  1. Plot the dial gauge reading (settlement) dd on the y-axis against the square root of time t\sqrt t on the x-axis.
  2. The initial part of the curve is a straight line (theoretical curve up to U=60%U = 60\%). Extend it back to cut the y-axis at the corrected zero reading d0d_0 (this corrects for initial compression).
  3. Draw a second line from d0d_0 with abscissa 1.15 times the first (the slope of the line is 1/1.15 of that of the first line).
  4. The intersection of this second line with the experimental curve gives t90\sqrt{t_{90}}, for 90% consolidation.
  5. Compute the coefficient of consolidation, using Tv=0.848T_v = 0.848 at U=90%U = 90\%:
cv=0.848 Hdr2t90c_v = \frac{0.848\,H_{dr}^2}{t_{90}}

where HdrH_{dr} is the average drainage path during the load increment (half the average specimen thickness for double drainage).

✓ Answer checked by Claude Opus 5.5 (high effort)

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