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Closed/open traverse, Bowditch's rule

Short answer

A closed traverse ends at the starting point or on known stations, providing a mathematical check; an open traverse ends at an unknown point. Bowditch's rule distributes the closing error in latitude and departure among lines in proportion to their lengths, assuming equal precision and accidental errors only.

What are closed and open traverses? Explain Bowditch's rule for balancing the traverse.

Closed and open traverses

  • Closed traverse: a traverse that ends where it began (a closed loop) or that starts and ends on stations of known position (a closed link/connecting traverse). It gives a mathematical check on the field work.
  • Open traverse: a traverse that starts at a known station and ends at a point of unknown position, so there is no closing check. It is used for roads, canals, pipelines and similar route surveys, and the angles and lengths must be checked by repeat measurement.

Bowditch's rule

Bowditch (compass) rule: the closing error in latitude and departure is distributed among the lines in proportion to their lengths.

CL=−ΣLat×lΣl,CD=−ΣDep×lΣlC_L=-\Sigma L_{at}\times\frac{l}{\Sigma l},\qquad C_D=-\Sigma D_{ep}\times\frac{l}{\Sigma l}

where ll is the length of the line and Σl\Sigma l the perimeter (or total length of the traverse).

Assumptions:

  • Angular and linear measurements are of equal precision, and the errors are accidental (random) only.
  • The error in the linear measurement of a line is proportional to l\sqrt{l}, and the error in angular measurement is inversely proportional to l\sqrt{l}. On these assumptions, the correction to the latitude and departure of each line works out to be proportional to its length.
  • The angular misclosure has already been distributed among the angles before the rule is applied.

It is simple, and it is the most commonly used rule in plane surveying.

Example

A four-sided closed traverse has ΣL = 494.58 m, with the computed latitudes and departures below. The errors are eN=ΣLat=+0.26e_N=\Sigma\text{Lat}=+0.26 m and eE=ΣDep=−0.13e_E=\Sigma\text{Dep}=-0.13 m, so e=0.291e=0.291 m and the precision is 1:17011:1701.

LineL (m)LatDepCorr. latCorr. depAdj. latAdj. dep
AB99.97+85.20+52.30-0.053+0.026+85.15+52.33
BC149.85+30.10+146.80-0.079+0.039+30.02+146.84
CD119.96-92.40-76.50-0.063+0.032-92.46-76.47
DA124.80-22.64-122.73-0.066+0.033-22.71-122.70

Check: the corrections add up to −eN-e_N and −eE-e_E, so the corrected latitudes and departures sum to zero. For line AB: Clat=−(+0.26)×99.97/494.58=−0.053C_{lat}=-(+0.26)\times99.97/494.58=-0.053.

✓ Answer checked by Claude Opus 5.5 (high effort)

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