- Asked 16/22
- 2074 Asoj · 8 marks
Address-format code for X=(A*B/C)-(D+E/F)
Short answer
Using postfix form A B * C / D E F / + -, the operation needs 5 three-address, 9 two-address, 9 one-address (accumulator) and 12 zero-address instructions. Fewer addresses per instruction reduce instruction length but increase count.
Write codes using 3, 2, 1 and 0 address instruction formats to perform the operation X = (A*B/C)-(D+E/F).
Assumptions: the operands are memory locations, R1, R2, ... are CPU registers, T1, T2, ... are temporary memory locations, and X receives the result. Multiplication and division are done before addition and subtraction, and equal-priority operators go left to right.
Fully bracketed: X = ((A*B)/C)-(D+(E/F)). Postfix (reverse Polish) form: A B * C / D E F / + -.
Three-address instructions (OP dest, src1, src2)
MUL R1, A, B ; R1 = A * B
DIV R2, R1, C ; R2 = R1 / C
DIV R3, E, F ; R3 = E / F
ADD R4, D, R3 ; R4 = D + R3
SUB X, R2, R4 ; X = R2 - R4
Number of instructions: 5. Shortest program, but each instruction is long (three addresses).
Two-address instructions (OP dest, src; dest = dest OP src)
MOV R1, A ; R1 = A
MUL R1, B ; R1 = R1 * B
DIV R1, C ; R1 = R1 / C
MOV R2, D ; R2 = D
MOV R3, E ; R3 = E
DIV R3, F ; R3 = R3 / F
ADD R2, R3 ; R2 = R2 + R3
SUB R1, R2 ; R1 = R1 - R2
MOV X, R1 ; X = R1
Number of instructions: 9. A MOV is needed first because the destination operand is overwritten.
One-address instructions (accumulator AC is the implied operand)
LOAD E ; AC = E
DIV F ; AC = AC / F
ADD D ; AC = AC + D
STORE T1 ; T1 = AC
LOAD A ; AC = A
MUL B ; AC = AC * B
DIV C ; AC = AC / C
SUB T1 ; AC = AC - T1
STORE X ; X = AC
Number of instructions: 9. Intermediate results that cannot stay in AC are saved in memory temporaries.
Zero-address instructions (stack machine)
PUSH A ; push A
PUSH B ; push B
MUL ; pop two, compute, push result
PUSH C ; push C
DIV ; pop two, compute, push result
PUSH D ; push D
PUSH E ; push E
PUSH F ; push F
DIV ; pop two, compute, push result
ADD ; pop two, compute, push result
SUB ; pop two, compute, push result
POP X ; X = top of stack
Number of instructions: 12. Only PUSH and POP carry an address; ADD, SUB, MUL, DIV work on the top two stack items, so the program follows the postfix form directly.
Summary: 3-address = 5, 2-address = 9, 1-address = 9, 0-address = 12 instructions. Fewer addresses per instruction means shorter instructions but more of them.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Address-format code for Y=(A+B)*(C+D) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for X=(P+Q)×(R+S) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=A*(B+D/C)+(G*E)/F · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=A/(B+C)+(D+E)*F · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(A+B)*(C+D)+G/E*F · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for X=(A-B*F)*C+D/E · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=A/B+(C×D)+F(H/G) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=AB+(C/D)+E(F/G) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(A-B+C)*(E+F/G) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(A-B/C)×(D+E×G)/F · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(A-B/C)*[D+(E*G)] · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(W+X)*(Y-Z) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=(A+B)/C+D/(E*F) · Computer Organization and Architecture, chapter 2 · asked 16×
- Address-format code for Y=AB+(F/G)+CD · Computer Organization and Architecture, chapter 2 · asked 16×
- Instruction fields and address formats for X=(E+F)*(G+H) · Computer Organization and Architecture, chapter 2
- Instruction and data format, addressing modes · Microprocessor, chapter 2 · asked 2×
- Datapath operation and instruction cycles · Embedded System, chapter 2
- Convolutional vs block codes; (7,4) cyclic code for 1011 · Communication Systems, chapter 8 · asked 2×
All Computer Organization and Architecture chapter 2 questions →