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Abrams' law of concrete strength

Short answer

Abrams' law states that concrete strength is inversely proportional to the water-cement ratio: f_c = A / B^{w/c}. Lower w/c yields higher strength because excess water leaves capillary pores. Valid for fully compacted workable mixes.

Describe Abrams' law of concrete.

Abrams' law (D. A. Abrams, 1918) states that for a given set of materials and age, the strength of fully compacted concrete is inversely related to the water-cement ratio: the lower the w/c ratio, the higher the strength.

fc=AB w/cf_c = \frac{A}{B^{\,w/c}}

where fcf_c is the compressive strength, w/cw/c is the water-cement ratio by mass, and AA, BB are empirical constants depending on the cement, age, curing and testing (Abrams: A=96.5A = 96.5 MPa, B=7B = 7 for 28 days).

 f_c
  |\
  | `.
  |   `-.
  |      `--.____
  +----------------> w/c

Explanation: only about 0.23-0.38 of the cement mass of water is needed for hydration; the extra water evaporates leaving capillary pores, which weaken the paste, so strength falls rapidly as w/c increases. The law is valid only for workable mixes that can be fully compacted.

✓ Answer checked by Claude Opus 5.5 (high effort)

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